Y=log(x-3)what would be the base?

1 answer:

4 0

By definition, if :

$a^y = b$

$y = log_a b$

We highlight the following elements:

a = Base of the logarithm;
b = logarithmand or antilogarithm
y = logarithm

Therefore:

Note that since the base was not specified, we know that it is equal to 10.

$y = log_a b$
$y = log_{10} (x-3)$
$10^y = (x-3)$

Answer:

Base of the logarithm = 10

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