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nexus9112 [7]
4 years ago
10

5. The difference between 3 number. difference between 31 and a number is 27. Find the

Mathematics
1 answer:
Yanka [14]4 years ago
5 0

Answer:

The number is 58

Step-by-step explanation:

31+27

58

58-31=27

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You need to buy some chicken for dinner tonight. You found an ad showing that the store across town has it on sale for $3.19 a p
SSSSS [86.1K]

Answer:

Yes, it is worth the extra drive, going to the further store is cheaper.

The cheaper option saves you $0.89.


Step-by-step explanation:

1.) Neighborhood store

It is 2.4 miles away

The car averages about 25 miles per gallon, then you would need:

2.4 miles / (25 miles/gallon) = 0.096 gallons of gas < 13 gallons (Ok)

The gas is about $3.89/gallon, then the gas would cost:

0.096 gallons * ($3.89/gallon) = $0.37344 = $0.37

The chicken is sold for $3.49 a pound, and you need 6 pounds, then you would pay:

6 pounds * ($3.49/pound) = $20.94

In total you would need:

$0.37 (gas) + $20.94 (chiken) = $21.31 if you buy the chicken in the neiborhood store

2.) Store acroos town

It is 8.2 miles away

The car averages about 25 miles per gallon, then you would need:

8.2 miles / (25 miles/gallon) = 0.328 gallons of gas < 13 gallons (Ok)

The gas is about $3.89/gallon, then the gas would cost:

0.328 gallons * ($3.89/gallon) = $1.27592 = $1.28

The chicken is sold for $3.19 a pound, and you need 6 pounds, then you would pay:

6 pounds * ($3.19/pound) = $19.14

In total you would need:

$1.28 (gas) + $19.14 (chiken) = $20.42 if you buy the chicken in the store across town


$20.42 < $21.31, then it is worth the extra drive, going to the further store is cheaper.

The cheaper option saves you: $21.31-$20.42=$0.89


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Step-by-step explanation:

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Step-by-step explanation:

Plug the x values into the equation

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y=-3(0)=0

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4 0
3 years ago
Simplify the expression. –16 • 1/8 • 4 + 32 ÷ 2
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Answer:

8

Step-by-step explanation:

–16 • 1/8 • 4 + 32 ÷ 2

Using PEMDAS, we multiply and divide from left to right since there are no parentheses or exponents.

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