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mestny [16]
2 years ago
11

Which of the following gives all of the sets that contain √9?

Mathematics
1 answer:
romanna [79]2 years ago
7 0

Soldiers for the nation of Gilead. “Blessed Be the Fruit”: The standard greeting amongst Gilead residents. The traditional reply is “May the Lord open.” “Under His Eye”: The Gileadean equivalent of “Aloha” — it works as both a hello and a goodbye.

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Rewrite in simplest terms: (x+10y)-(x+5y)(x+10y)−(x+5y)
Solnce55 [7]

Answer:

-x^2-15xy-50y^2+14y

Step-by-step explanation:

3 0
3 years ago
Mary invested $5000 in the bank. How much money does she have at the end of 15 years if the interest rate is 4.5% per annum ? A
NARA [144]

Answer:

350000

Step-by-step explanation:

I'm not sure

but I got this one

3 0
3 years ago
Given the functions f(x)=2x^2-3x-8 and g(x)=3x2+5x+1
kykrilka [37]

Answer:

B

Step-by-step explanation:

the product (2x² - 3x - 8)(3x² + 5x + 1) is required

multiply each term in the second factor by each term in the first factor.

= 2x²(3x² + 5x + 1) - 3x(3x² + 5x + 1) - 8(3x² + 5x + 1) ← distribute

= 6x^{4} + 10x³ + 2x² - 9x³ - 15x² - 3x - 24x² - 40x - 8

collecting like terms gives

6x^{4} + x³ - 37x² - 43x - 8 → B


8 0
3 years ago
What is true about the solution of x^2/2x-6=9/6x-18?
pogonyaev

Answer:

  • x = ±√3, and they are actual solutions
  • x = 3, but it is an extraneous solution

Step-by-step explanation:

The method often recommended for solving an equation of this sort is to multiply by the product of the denominators, then solve the resulting polynomial equation. When you do that, you get ...

... x^2(6x -18) = (2x -6)(9)

... 6x^2(x -3) -18(x -3) = 0

...6(x -3)(x^2 -3) = 0

... x = 3, x = ±√3

_____

Alternatively, you can subtract the right side of the equation and collect terms to get ...

... x^2/(2(x -3)) - 9/(6(x -3)) = 0

... (1/2)(x^2 -3)/(x -3) = 0

Here, the solution will be values of x that make the numerator zero:

... x = ±√3

_____

So, the actual solutions are x = ±3, and x = 3 is an extraneous solution. The value x=3 is actually excluded from the domain of the original equation, because the equation is undefined at that point.

_____

<em>Comment on the graph</em>

For the graph, we have rewritten the equation so it is of the form f(x)=0. The graphing program is able to highlight zero crossings, so this is a convenient form. When the equation is multiplied as described above, the resulting cubic has an extra zero-crossing at x=3 (blue curve). This is the extraneous solution.

7 0
3 years ago
Read 2 more answers
Can you help me out ​
Advocard [28]
The answer is 20

Your welcome
8 0
2 years ago
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