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GuDViN [60]
2 years ago
12

Consider the right rectangular prism.

Mathematics
2 answers:
patriot [66]2 years ago
8 0
It’s b the fcc and I have been playing it on my iPad for the last two days and I’m bout to go get some sleep and I’m sleep over the phone with me lol I love y’all so I love y’all playing with you guys I don’t have a lot to say I’m sorry I’m not working lol I’m bout to go get some rest lol lol I love y’all so I don’t want you guys here I love y’all so I don’t want you
NARA [144]2 years ago
7 0

Answer:

B

Please mark brainliest if correct

Step-by-step explanation:

We can rule out A and D because of the area.

The area of a cube with side length 1/4 is 1/64, times 840, is 13 1/8

The area of a cube with side length 1/2 is 1/8, times 420, is 52 1/2

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A survey was conducted in the United Kingdom, where respondents were asked if they had a university degree. One question asked,
katovenus [111]

Answer:

z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620  

p_v =2*P(Z>1.620)=0.105  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

Step-by-step explanation:

Data given and notation  

X_{1}=45 represent the number of correct answers for university degree holders

X_{2}=57 represent the number of correct answers for university non-degree holders  

n_{1}=373 sample 1 selected

n_{2}=639 sample 2 selected

p_{1}=\frac{45}{373}=0.121 represent the proportion of correct answers for university degree holders  

p_{2}=\frac{57}{639}=0.0892 represent the proportion of correct answers for university non-degree holders  

z would represent the statistic (variable of interest)  

p_v represent the value for the test (variable of interest)

Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the proportions are different between the two groups, the system of hypothesis would be:  

Null hypothesis:p_{1} = p_{2}  

Alternative hypothesis:p_{1} \neq p_{2}  

We need to apply a z test to compare proportions, and the statistic is given by:  

z=\frac{p_{1}-p_{2}}{\sqrt{\hat p (1-\hat p)(\frac{1}{n_{1}}+\frac{1}{n_{2}})}}   (1)

Where \hat p=\frac{X_{1}+X_{2}}{n_{1}+n_{2}}=\frac{45+57}{373+639}=0.101

Calculate the statistic

Replacing in formula (1) the values obtained we got this:  

z=\frac{0.121-0.0892}{\sqrt{0.101(1-0.101)(\frac{1}{373}+\frac{1}{639})}}=1.620  

Statistical decision

For this case we don't have a significance level provided \alpha, but we can calculate the p value for this test.  

Since is a one side test the p value would be:  

p_v =2*P(Z>1.620)=0.105  

If we compare the p value and using any significance level for example \alpha=0.05 always p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can say the the two proportions are not statistically different at 5% of significance

7 0
3 years ago
What is the width of a rectangle with length 14 cm and area 161 cm to the 2nd power?
WINSTONCH [101]
A=l*w
161=14w

161/14=w

11.5cm is the width
7 0
3 years ago
Last month Marybeth was charged $112for a 945kWh of electricity. How much did the company charger her per kWh, to the nearest ce
Usimov [2.4K]
She was charged 12 cents per kWh
3 0
3 years ago
Read 2 more answers
Please Help!!!!!!!!!!!!!!!!!!!!!!
expeople1 [14]

Answer:

C

isn't that the NWEA test

7 0
3 years ago
Henry packed some apples in a box. The total mass of the box and the apples was 16 240 g. He packed some strawberries in a simil
icang [17]

Step-by-step explanation:

x = mass of apples

y = mass of strawberries

z = mass of the box

x = 3y

x + z = 16240

y + z = 6350

let's subtract the second from the first equation

x + z = 16240

- y + z = 6350

-----------------------

x - y + 0 = 9890

using the first identity in that result gives us

3y - y = 9890

2y = 9890

y = 4,945 g

x = 3y = 3×4945 = 14,835 g = the mass of the apples

3 0
2 years ago
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