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Burka [1]
3 years ago
8

Explain in math 8th grade - what mean, median and mode are?

Mathematics
2 answers:
irinina [24]3 years ago
7 0
Mean - is the average of something. You basically find the sum of all the numbers then divide the sum by how many numbers you added so for example I have 1,3,4and 2
To find the average you add them first to get 10 then you divide this by 4 since I added 4 numbers.

Median - is the number that falls in the middle. First you gotta sort the numbers from smallest to biggest then pick the one in the middle for example is I have 7,5,9,2and 1. I gotta sort it —-> 1,2,5,7,9 then I pick the number in the middle which is 5. So 5 is the median

Mode- is the number that appears the most times. So if I have the set 3,7,5,3,9,4,1,3 the mode would be 3 because it appears the most times
mina [271]3 years ago
3 0
Mean is the average

To calculate mean
Eg: 2, 5, 9, 3, 5, 4 7
There are 7 digits
(2+5+9+3+5+4+7) divide by 7
= 5 is the mean

Median is the middle value

To calculate mean, you have to reorder the data in a numerical order. Median is always the middle value so in this case: 5 is the middle value.

2, 5, 9, 3, 5, 4, 7
Ordered correctly: 2,3,4,5,5,7, 9
=5 is the median value

Mode is the most repeated number on the list, so for this care, the Mode is 5 because there are two “5” digits in this data.
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Cos(x+y)/cosxcosy+tanxtany=1
adelina 88 [10]

Answer:

See explanation

Step-by-step explanation:

Use formula

\cos (x+y)=\cos x\cos y-\sin x\sin y

Substitute it into the first fraction:

\dfrac{\cos (x+y)}{\cos x\cos y}\\ \\=\dfrac{\cos x\cos y-\sin x\sin y}{\cos x\cos y}\\ \\=\dfrac{\cos x\cos y}{\cos x\cos y}-\dfrac{\sin x\sin y}{\cos x\cos y}\\ \\=1-\dfrac{\sin x}{\cos x}\cdot \dfrac{\sin y}{\cos y}\\ \\=1-\tan x\tany

Consider the whole expression:

\dfrac{\cos (x+y)}{\cos x\cos y}+\tan x\tan y\\ \\=1-\tan x \tan y+\tan x\tan y\\ \\=1

Done!

6 0
3 years ago
PLEASE ANSWER QUICK. LOTS OF POINTS
AnnZ [28]

Answer:

c is the answer I'm sure

4 0
4 years ago
What value of x is in the solution set of 4x - 12 S 16 + 8x?
Jobisdone [24]

You gave little context, so here is a few solutions.

POSSIBLE #1:

assuming s is a variable

---> Simplify  12S × 16 to 192S

4x-192S+8x

--->  Collect like terms.

(4x+8x)-192S

---> Simplify.

12x-192S

POSSIBLE #2: (assuming s is not relevant)

Simplifying

4x + -12 = 16 + 8x

Reorder the terms:

-12 + 4x = 16 + 8x

Solving

-12 + 4x = 16 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.

-12 + 4x + -8x = 16 + 8x + -8x

Combine like terms: 4x + -8x = -4x

-12 + -4x = 16 + 8x + -8x

Combine like terms: 8x + -8x = 0

-12 + -4x = 16 + 0

-12 + -4x = 16

Add '12' to each side of the equation.

-12 + 12 + -4x = 16 + 12

Combine like terms: -12 + 12 = 0

0 + -4x = 16 + 12

-4x = 16 + 12

Combine like terms: 16 + 12 = 28

-4x = 28

Divide each side by '-4'.

x = -7

Simplifying

x = -7

If there are any other ways to solve this please add more context in the comments below this answer! Hope this was helpful! Have a marvelous day/night!

4 0
3 years ago
Write the following expression using symbolic language.
Ad libitum [116K]

Answer:

<h3>              1)   7x - 5 </h3><h3>              2)   9y - 18 </h3><h3>              3)   0.5n + 4n </h3><h3>              4)  2(w³+23)</h3><h3> Step-by-step explanation:</h3>

1)

The product of seven and a number x:   7·x = 7x

<u>Five less than the product of seven and a number x:</u>

<h3>7x - 5 </h3>

2)

nine times a number y:  9·y = 9y

<u>The difference of nine times a number y and eighteen:</u>

<h3>9y - 18 </h3>

3)

half a number n:   0.5n

four times the number:   4·n = 4n

<u>Half a number n increased by four times the number:</u>

<h3>0.5n + 4n </h3>

4)

a number w cubed:  w³

the sum of a number w cubed and twenty-three:  w³+23

<u>Twice the sum of a number w cubed and twenty-three:</u>

<h3>2(w³+23)</h3>

5 0
3 years ago
Did I get all of those questions right?
egoroff_w [7]
Looks good to me but I’m not the best at math. Sorry I couldn’t be a huge help.
4 0
3 years ago
Read 2 more answers
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