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Gelneren [198K]
3 years ago
10

Did I get all of those questions right?

Mathematics
2 answers:
zysi [14]3 years ago
5 0
Yes Yhu Got All your answers correct
egoroff_w [7]3 years ago
4 0
Looks good to me but I’m not the best at math. Sorry I couldn’t be a huge help.
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Damien deposited $250 in an account that earned 3.75% interest compounded annually.
nordsb [41]
Your answer will be
250(1+3.75/100)^4
=289.66260375977
Nearest to =289.7

6 0
3 years ago
Given g(x) = 3x + 3 , find g(k)
xxTIMURxx [149]

Answer:

3k+3

Step-by-step explanation:

6 0
3 years ago
A triangle with base 6. and height 3 in. Whats the answer and please show work
motikmotik
How you find the area of a triangle is base × height ÷ 2. So the equation would be 6×3=18 18÷2=9, so the answer is 9. Hope this helped!
4 0
3 years ago
Read 2 more answers
Help pls! Brainliest!
blagie [28]

Answer:

y =-3000x +12000

Step-by-step explanation:

answer is

1)   12000 is the constant therefore when the number of hours is 0 the tickets are 12000

2)  the number of tickets (y) are reducing by 3000 for each hour(x). thus the coefficient of variable x should be -3000  (negative because it is reducing)

8 0
3 years ago
A study of pollutants showed that certain industrial emissions should not exceed 2.3 parts per million. You believe a particular
Musya8 [376]

Answer:

t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5    

The degrees of freedom are given by:

df=n-1=9-1=8  

And the p value would be:

p_v =P(t_{(8)}>7.5)=0.0000346  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

Step-by-step explanation:

Information provided

\bar X=3.3 represent the sample mean in ppm

s=0.4 represent the sample standard deviation

n=9 sample size  

\mu_o =2.3 represent the value to verify

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value

System of hypothesis

We want to verify if the true mean is higher than 2,3 ppm, the system of hypothesis would be:  

Null hypothesis:\mu \leq 2.3  

Alternative hypothesis:\mu > 2.3  

The statistic for this case is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info given we got:

t=\frac{3.3-2.3}{\frac{0.4}{\sqrt{9}}}=7.5    

The degrees of freedom are given by:

df=n-1=9-1=8  

And the p value would be:

p_v =P(t_{(8)}>7.5)=0.0000346  

Since the p value is lower than the significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 2.3 ppm the safe limit

6 0
3 years ago
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