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lilavasa [31]
3 years ago
7

Tyler has 3 times as many books as Mai. How many books does Mai have if Tyler has x books?

Mathematics
1 answer:
arlik [135]3 years ago
6 0
It should be the first one, or 3x, I’m pretty sure because x is going to be the amount that he has and he has 3 times the amount or something
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(3t^2+1)-t^2. How do you do this equation and what’s the answer. Algebra 1.
Oksana_A [137]

2t^2+1

Subtract t^2 from 3t^2 you get 2t^2

which is 2t^2+1 answer

3 0
3 years ago
Add 34+(−212) using the number line. Select the location on the number line to plot the sum.
nexus9112 [7]

Answer:

-1 3/4

Step-by-step explanation:

3/4 + (-2 1/2)

3/4 - 2

-1 3/4

5 0
3 years ago
In the figure above, the vertices of square
Olin [163]

(C) 6 + 3√3

<u>Explanation:</u>

Area of the square = 3

a X a = 3

a² = 3

a = √3

Therefore, QR, RS, SP, PQ = √3

ΔBAC ≅ ΔBQR

Therefore,

\frac{BQ}{BA} = \frac{QR}{AC}

\frac{BQ}{BA} = \frac{\sqrt{3} }{BA}

In ΔBAC, BA = AC = BC because the triangle is equilateral

So,

BQ = √3

So, BQ, QR, BR = √3 (equilateral triangle)

Let AP and SC be a

So, AQ and RC will be 2a

In ΔAPQ,

(AP)² + (QP)² = (AQ)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

Similarly, in ΔRSC

(SC)² + (RS)² = (RC)²

(a)² + (√3)² = (2a)²

a² + 3 = 4a²

3 = 3a²

a = 1

So, AP and SC = 1

and AQ and RC = 2 X 1 = 2

Therefore, perimeter of the triangle = BQ + QA + AP + PS + SC + RC + BR

Perimeter = √3 + 2 + 1 + √3 + 1 + 2 + √3

Perimeter = 6 + 3√3

Therefore, the perimeter of the triangle is 6 + 3√3

8 0
2 years ago
<img src="https://tex.z-dn.net/?f=%20-%203y%20%7B%7D%5E%7B2%7D%20%3D%20%20-%2075" id="TexFormula1" title=" - 3y {}^{2} = - 75"
Paraphin [41]

Answer:

The answer will turn out to be y= 5 or y= -5.

7 0
3 years ago
Use the following compound interest formula to complete the problem currently you have two credit cards H and die card H has a b
abruzzese [7]

Answer:

  card I by $82.50

Step-by-step explanation:

As you know the compound interest formula is ...

  A = P(1 +r/n)^(nt)

For card H, P=1186.44, r=0.1474, n=1, t=3, so the balance will be ...

  A = $1186.44(1.1474^3) ≈ $1792.22

For card I, P=1522.16, r=0.125, n=12, t=3, so the balance will be ...

  A = $1522.16(1 +.125/12)^(12·3) ≈ $2210.44

__

The increase in card H is ...

  $1792.22 -1185.44 = $605.78

The increase in card I is ...

  $2210.44 -1522.16 = $688.28 . . . . . . card I increased more

The difference in the increases is ...

  $688.28 -605.78 = $82.50

Card I increased by $82.50 more than card H in the time period.

5 0
3 years ago
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