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3 years ago

A town's yearly snowfall in inches over a 10-year period is recorded in this table.

Mathematics

1 answer:

irinina [24]3 years ago

5 0

Answer:

18.8

14+12+21+26+19+15+22+17+24+18 = 188 188/10

I don't remember how to do stem and leaf plots.

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Please help ASAP. PRE ALGEBRA

telo118 [61]

Answer:

x=35

Angle measurements of the triangle from least to greatest:

35,40,105

Step-by-step explanation:

The sum of the angles of a triangle is 180 degrees.

So we know that 40+3x+x=180.

First step is to combine the like terms on the left hand side:

40+4x=180

Second step is to subtract 40 on both sides.

4x=140

Third step is to divide both sides by 4:

x=35

The angle that is given is the one that is 40 degrees.

So the angle whose measurement is x is really 35 degrees.

The angle whose measurement is 3x is real 3(35)=105 degrees.

In order from least to greatest we have:

35,40,105

6 0

3 years ago

Carlos read 144 pages in 3 hours. His little sister read 24 pages in 1 hour. carlos's average reading rate is what percent of hi

ehidna [41]

Hello! So Carlos' sister reads an average of 24 pages in 1 hour. He reads 144 pages in 3 hours. To find the unit rate Carlos reads, let's do some division. 144/3 is 48. Carlos reads an average of 48 pages in 1 hour. If you use mental math, 48 is double the amount of 24. 200% is just simply 2. 24 * 2 is 48. D is the only one that shows an answer that even fits for this scenario. Carlos' average reading rate is 200% of his sister's. The answer is D: 200%.

3 0

3 years ago

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What did the lady say about her brain surgeon

Gekata [30.6K]

I really gave him a piece of my mind

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3 years ago

student randomly receive 1 of 4 versions(A, B, C, D) of a math test. What is the probability that at least 3 of the 5 student te

alexdok [17]

Answer:

1.2%

Step-by-step explanation:

We are given that the students receive different versions of the math namely A, B, C and D.

So, the probability that a student receives version A = $\frac{1}{4}$ .

Thus, the probability that the student does not receive version A = $1-\frac{1}{4}$ = $\frac{3}{4}$ .

So, the possibilities that at-least 3 out of 5 students receive version A are,

1) 3 receives version A and 2 does not receive version A

2) 4 receives version A and 1 does not receive version A

3) All 5 students receive version A

Then the probability that at-least 3 out of 5 students receive version A is given by,

$\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{3}{4}$ + $\frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}\times \frac{1}{4}$