A rental car company charges $38.38 per day to rent a car and $0.14 for every mile driven. Camden wants to rent a car, knowing t
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Answer:
V = 128π/3 vu
Step-by-step explanation:
we have that: f(x)₁ = √(4 - x²); f(x)₂ = -√(4 - x²)
knowing that the volume of a solid is V=πR²h, where R² (f(x)₁-f(x)₂) and h=dx, then
dV=π(√(4 - x²)+√(4 - x²))²dx; =π(2√(4 - x²))²dx ⇒
dV= 4π(4-x²)dx , Integrating in both sides
∫dv=4π∫(4-x²)dx , we take ∫(4-x²)dx and we solve
4∫dx-∫x²dx = 4x-(x³/3) evaluated -2≤x≤2 or too 2 (0≤x≤2) , also
∫dv=8π∫(4-x²)dx evaluated 0≤x≤2
V=8π(4x-(x³/3)) = 8π(4.2-(2³/3)) = 8π(8-(8/3)) =(8π/3)(24-8) ⇒
V = 128π/3 vu
Answer:
Graph B
No
Inside
Step-by-step explanation:
Let, the number of apples = x and number of peaches = y.
It is given that the farmer can afford maximum of 54 acres.
Thus, x + y ≤ 54.
Also, apples require 3000 gallons of water and peaches require 800 gallons of water each day.
Since, maximum amount of water is 80,000 gallons per day,
We get, 3000x + 800y ≤ 80,000.
It is required to maximize the profit given by z = 3400x + 1600y.
Thus, the system of equations becomes,
z = 3400x + 1600y
3000x + 800y ≤ 80,000.
x + y ≤ 54.
Plotting these equations gives the following graph.
We can see that the graph obtained is equivalent to Graph B.
Further, we know that the maximum value of the objective function z = 3400x + 800y is obtained at the boundary point of the solution region.
Thus, any point inside the solution region will give a feasible solution not maximum solution.
Hence, ( 30,20 ) will not maximize the profit as it lies inside the solution region.
