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3 years ago

Simplify.

1 answer:

8 0

First off, nicely done on the exponents. You'd be surprised on how bad some look ,:D

a)
$(3xy^{3})(2x^{2}y)\\ (3*2)(x*x^{2})(y^{3}*y)\\\\ 6x^{3}y^{4}$

b)
$2y(2y+3y^{2})-y^{2}(3-y)\\ (4y^{2}+6y^{3}) + (-3y^{2}+y^{3})\\ (6y^{3}+y^{3})+(4y^{2}-3y^{2})\\ 7y^{3}+y^{2}\\\\ y^{2}(7y+1)$

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Assuming all other requirements are met, which of the following taxpayers do NOT qualify for the 2021 Earned Income Tax Credit?

Ilia_Sergeevich [38]

Based on the information given, the person who doesn't qualify for the income tax credit will be A. Ivy, age 22, is single with no dependents. She is not a dependent of another person. She has wages of $6,500 and an investment income of $11,150.

It should be noted that the earned income tax credit is important as it helps low-income workers get a tax break.

From the options given, Ivy is the taxpayer that does not qualify for the 2021 Earned Income Tax Credit. This is because she's not a dependent of another person.

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2 years ago

Sean's new baby brother weighs 125.2 ounces. A nurse writes the weight in the chart rounded to the nearest ounce. Which is the w

Naily [24]

The answer would have to be A because if it's ROUNDED to the nearest ounce then 2 is closer to 0 so it would be A

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3 years ago

This Venn diagram shows the pizza topping preferences for 9 students. Let event A = The student likes pepperoni. Let event B = T

victus00 [196]

Answer:

$P(A\ or\ B)=\frac{7}{9}$

Step-by-step explanation:

We need to use the formula to calculate the probability of (A or B) where

A=Probability a student likes pepperoni

B=Probability a student likes olive

A and B =Probability a student likes both toppings in a pizza

A or B =Probability a student likes pepperoni or olive (and maybe both), a non-exclusive or

The formula is

$P(A\ or\ B)=P(A)+P(B)-P(A\ and\ B)$

Since 6 students like pepperoni out of 9:

$P(A) = \frac{6}{9}$

Since 4 students like olive out of 9:

$P(B) = \frac{4}{9}$

Since 3 students like both toppings out of 9

$P(A\ and\ B) = \frac{3}{9}$

Then we have

$P(A\ or\ B)=\frac{6}{9}+\frac{4}{9}-\frac{3}{9}$

$P(A\ or\ B)=\frac{7}{9}$

7 0

3 years ago

Find the slope of the line passing through the points(7,-3) and (2,-5) .

Contact [7]

I believe the slope will be 8/5

3 0

3 years ago

Read 2 more answers

Suppose we roll a fair six-sided die and sum the values obtained on each roll, stopping once our sum exceeds 307. Approximate th

SOVA2 [1]

Answer:

There is a probability of P=0.94 that at least 81 rolls are needed to get the sum of 307.

Step-by-step explanation:

The roll of a six-sided die sum has this parameters:

Mean: 3.5

Standard deviation: 1.7

If the die is rolled 81 times, the distribution of the sum of the 81 rolls will have the following parameters:

$\mu=n*M=81*3.5=283.5\\\\\sigma=\sqrt{n}s=\sqrt{81}*1.7=9*1.7=15.3$

Note: the variance of the sum of random variables is equal to the sum of the variance of the individual variables.

Then, we can calculate the probabilties that the sum of 81 rolls is lower than 307.

$z=\frac{x-\mu}{\sigma}=\frac{307-283.5}{15.3}= \frac{23.5}{15.3}= 1.536\\\\\\P(x$

There is 94% of chances that the sum of 81 rolls is lower than 307, so there is a probability of P=0.94 that at least 81 rolls are needed to get the sum of 307.

5 0

3 years ago