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Allisa [31]
3 years ago
6

What is a good estimate for 1,710 2,740 4.322 5,700 7,810 6,395

Mathematics
1 answer:
timama [110]3 years ago
3 0

Answer:

What do you mean by a "Good estimate"? There's no picture or questions.

Step-by-step explanation:

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They are all prime numbers.
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I need to know 9 and 3/4 multiplied by 15 and 1/2
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9 3/4 x 15 1/2
= 151 1/8
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= 151.125
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Pine Bluff Middle School is having its annual Spring Fling dance, which will cost $400. The student treasurer reported that the
Jet001 [13]
Is the real anwser 479
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3 years ago
Below are the heights (in inches) of students in a third-grade class. Find the median height. 39, 37, 48, 49, 40, 42, 48, 53, 47
Nutka1998 [239]

Given:

The heights (in inches) of students in a third-grade class are:

39, 37, 48, 49, 40, 42, 48, 53, 47, 42, 49, 51, 52, 45, 47, 48

To find:

The median height.

Solution:

The given data set is:

39, 37, 48, 49, 40, 42, 48, 53, 47, 42, 49, 51, 52, 45, 47, 48

Arrange the data set in ascending order.

37, 39, 40, 42, 42, 45, 47, 47, 48, 48, 48, 49, 49, 51, 52, 53

Here, the number of observations is 16. So, the median of the given data set is:

Median=\dfrac{\dfrac{n}{2}\text{th term}+\left(\dfrac{n}{2}+1\right)\text{th term}}{2}

Median=\dfrac{\dfrac{16}{2}\text{th term}+\left(\dfrac{16}{2}+1\right)\text{th term}}{2}

Median=\dfrac{8\text{th term}+9\text{th term}}{2}

Median=\dfrac{47+48}{2}

Median=\dfrac{95}{2}

Median=47.5

Therefore, the median height of the students is 47.5 inches.

5 0
3 years ago
A production facility employs 20 workers on the day shift, 15 workers on the swing shift, and 10 workers on the graveyard shift.
Pepsi [2]

Answer:

1. 77520

2. P_1 = 0.0017

3. P_2 = 0.0019

4. P_3 = 0.9981

5. P_4 = 0.2036

Step-by-step explanation:

The number of ways or combinations in which we can select x elements from a group of n can be calculated as:

nCx = \frac{n!}{x!(n-x)!}

So, there are 77520 selections that result in all 7 workers coming from the day shift. It is calculated as:

20C7 = \frac{20!}{7!(20-7)!}=77520

At the same way, the total number of selections of 7 workers from the 45 is 45C7, so the probability that all 7 selected workers will be from the day shift is:

P_1=\frac{20C7}{45C7} =0.0017

The probability that all 7 selected workers will be from the same shift is calculated as:

P_2=\frac{20C7+15C7+10C7}{45C7} =0.0019

Because the consultant can select all workers from the day shift (20C7) or can select all workers from the swing shift (15C7) or can select all workers from the graveyard shift (10C7).

On the other hand, the probability that at least two different shifts will be represented among the selected workers is the complement of the probability that all 7 selected workers will be from the same shift. So it is calculated as:

P_3 = 1- P_2=1 - 0.0019 = 0.9981

Finally, the probability that at least one of the shifts will be un-represented in that sample of workers is:

P_4=\frac{25C7+30C7+35C7}{45C7} =0.2036

Where 25C7 is the number of ways to select all 7 workers from swing or graveyard shift, 30C7 is the number of ways to select all 7 workers from day or graveyard shift and 35C7 is the number of ways to selects all 7 workers from day shift and swing shift.

6 0
3 years ago
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