Answer:
To construct the Square using a compass and straight edge, you have written the steps not in proper order. I am rearranging the steps for you
1. Construct horizontal H J¯¯¯¯¯
2. Construct a circle with point H as the center and a circle with point J as a center with each circle having radius HJ .
3.Label the point of intersection of the two circles above HJ¯¯¯¯¯ , point K, and the point of intersection of the two circles below HJ¯¯¯¯¯ , point L.
4.Construct KL¯¯¯¯¯ , the perpendicular bisector of HJ¯¯¯¯¯ , intersecting HJ¯¯¯¯¯ at point M.
5.Construct a circle with point M as the center with radius MJ .
6.Label the point of intersection of circle M and KL¯¯¯¯¯ closest to point K, point N, and the point of intersection of circle M and KL¯¯¯¯¯ closest to point L, point O.
7.Construct HN¯¯¯¯¯¯ , NJ¯¯¯¯¯ , JO¯¯¯¯¯ , and OH¯¯¯¯¯¯ to complete square HNJO .
The answer is C
So how?
I multiplied 48*.19= 9.12 then subtracted that from 48 and got 38.88 which rounds to 39
C is the answer
I hope this helps! :D
Answer:
erm
Step-by-step explanation:
25
Answer:
man you got this
Step-by-step explanation:
If f(x) = x + 9 and g(x) = 9x – 4, - 22024651. ... Click on the correct answer. 3 is not in the domain of fºg. 3 is in the domain of fºg. 1. See answer. Add answer+5 pts ... Answer: 3 is in the domain of f(g(x)). Step-by-step explanation: ... What is the domain of the given function? a) {x | x = –6, –1, 0, 3}; {y | y = –7, –2, ...
The domain is all real numbers except 9 (positive)
This is because we can't have 0 in the denominator, and when x equals 9, then the denominator is 0. Anything divided by 0 is undefined, which is why 9 (in this equation) is not included.
