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MrMuchimi
3 years ago
6

Simplify the following expression, 2(k - 9) + 12

Mathematics
1 answer:
Phoenix [80]3 years ago
8 0

Answer:

2k - 6

Step-by-step explanation:

Distribute:

2k - 18 + 12

Add:

2k - 6

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Which is greater 728.307 or 729.07
Nataly [62]

Answer:

729.07

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Arrange the geometric series from least to greatest based on the value of their sums.
son4ous [18]

Answer:

80 < 93 < 121 < 127

Step-by-step explanation:

For a geometric series,

\sum_{t=1}^{n}a(r)^{t-1}

Formula to be used,

Sum of t terms of a geometric series = \frac{a(r^t-1)}{r-1}

Here t = number of terms

a = first term

r = common ratio

1). \sum_{t=1}^{5}3(2)^{t-1}

   First term of this series 'a' = 3

   Common ratio 'r' = 2

   Number of terms 't' = 5

   Therefore, sum of 5 terms of the series = \frac{3(2^5-1)}{(2-1)}

                                                                      = 93

2). \sum_{t=1}^{7}(2)^{t-1}

   First term 'a' = 1

   Common ratio 'r' = 2

   Number of terms 't' = 7

   Sum of 7 terms of this series = \frac{1(2^7-1)}{(2-1)}

                                                    = 127

3). \sum_{t=1}^{5}(3)^{t-1}

    First term 'a' = 1

    Common ratio 'r' = 3

    Number of terms 't' = 5

   Therefore, sum of 5 terms = \frac{1(3^5-1)}{3-1}

                                                 = 121

4). \sum_{t=1}^{4}2(3)^{t-1}

    First term 'a' = 2

    Common ratio 'r' = 3

    Number of terms 't' = 4

    Therefore, sum of 4 terms of the series = \frac{2(3^4-1)}{3-1}

                                                                       = 80

    80 < 93 < 121 < 127 will be the answer.

4 0
3 years ago
Read 2 more answers
Help plssss idk what to do!!!!!!!!!
Firdavs [7]

9514 1404 393

Answer:

  y = 1

Step-by-step explanation:

Recognize that 25 and 125 are powers of 5 and rewrite the equation in terms of powers of 5.

The applicable rules of exponents are ...

  (a^b)^c = a^(bc)

  (a^b)/(a^c) = a^(b-c)

  (a^b)(a^c) = a^(b+c)

__

Your equation can be written as ...

  25^4\div5^{5y}=125^y\\\\(5^2)^4\div5^{5y}=(5^3)^y\\\\5^{8-5y}=5^{3y}\\\\8-5y=3y\qquad\text{equate exponents of the same base}

Now this can be solved as an ordinary linear equation.

  8 = 8y . . . . . . add 5y to both sides

  1 = y . . . . . . . divide by 8

The solution is y = 1.

4 0
3 years ago
Use x for the variable. <br>All real numbers less than or equal to 2 and greater than or equal to 1​
Kisachek [45]

Answer:xxwy

Step-by-step explanation:

By by 2

3 0
3 years ago
Write 2,000,947 in each form <br>Word <br>Expanded
NARA [144]
Two million, nine hundred forty seven

2,000,000+900+40+7
5 0
3 years ago
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