Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
A, since n=20 and p=5% if children are vaccinated mean number of new infections =np= 20*0.05=1 p(x<=2) = P(x=0)+P(x=1)
3. A square is a rhombus in which all the angles equal (to 90°).
4. 20 : 24 ratio that the ball picked wont be green
5. false
11. 15
12. half a chance (1/2)
13. 51
16. 9.79 × 10^-5
17. 4y = 29
18. b) 6.1
19. 80
20. x = -8/7
30. Area ≈ 7982.79
34. check the picture i attached for the histogram
THIS TOOK SO LONG
Answer: the width is 150
Step-by-step explanation:
Answer:
The answer to your question is: Letter A
Step-by-step explanation:
Data
M (-6, 7)
E (4, 11)
r = 1 / 3
Formula


x = 
y = 