Answer: 0.0304
Step-by-step explanation:
A z-test is a statistical test that is used to determine if two population means are different when the variances are known and the sample size is large. The test statistic is assumed to have a normal distribution, and nuisance parameters such as standard deviation should be known in order for an accurate z-test to be performed.
A z-statistic, also known as z-score, is a number representing how many standard deviations above or below the mean population a score derived from a z-test is.
Therefore,
sample size,n = 36
mean,u = 16 ounce
standard deviation,s = 0.2 pounds = 3.2 ounce
x = 15 ounce
z = (x-u) / (s/sqrt(n)) = -1.875
In conclusion, the probability that the amount dispensed by box will be increased is:
P(X<15) = P(Z<-1.875)
= 1 - P(Z<1.875)
= 1 - 0.9696
0.0304
The Answer is 0.0304.
For a known standard deviation, the confidence interval for sample size = n is

where
x = average
n = sample size

= stad. deviation
z = contant that reflects confidence interval
Let a = x
Let b =

From the given information,
a - b = 0.432 (1)
a + b = 0.52 (2)
Add (1) and (2): 2a = 0.952 => a = 0.476
Subtract (2) from (1): -2b = -0.088 => b = 0.044
Therefore, the confidence interval may be written as
(0.476 - 0.044, 0.476 + 0.044), or as
(0.476

0.044)
The answer is 5.83
Use the Pythagorean Theorem to calculate the 3rd side length.
a^2+b^2=c^2
3^2+5^2=c^2
9/16 of the family garden
We can use an equation to solve this:
(3/4) * (3/4) = (9/16)
41.=30°
43.=60°
45.=60°
47.=30°