Answer:
7 quarts
Step-by-step explanation:
you subtract the amount that the first aquarium can hold from the second amount
Answer:
The slope of the red line is also 8
Step-by-step explanation:
Parallel lines never meet. So, they always have the same slope. If they had different slopes, then they would meet on the graph at some point. However, since the lines have the same slope, they will never meet since they proportionally grow at the same rate.
It should be Expand by distributing terms.
8
×
7
+
8
x
8×7+8x
2 Simplify
8
×
7
8×7 to
5
6
56.
56+8x
ANSWER: 56+8x
Part A
Given that

Then,

For

, then

Thus,

For

, we have

Part B
Recall that from part A,

Now, at initial position, t = 0 and

, thus we have

and when the velocity drops to half its value,

and

Thus,

Thus, the distance the particle moved from its initial position to when its velocity drops to half its initial value is given by
Answer:
The range of the random variable is {0, 1, 2}.
Step-by-step explanation:
The bag contains red and blue marbles.
The experiments consists of two draws, with reposition.
The random variable assigns the number of blue marbles to each outcome.
If we have only two draws, we can only get 0, 1 or 2 blue marbles.
The range of the random variable is {0, 1, 2}.