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4 years ago

Help!NOW please!! I’ll do anything!

Mathematics

2 answers:

Serhud [2]4 years ago

8 0

Answer:

re08uwahrewrai098nyryvrhheuaviufvsdsavad <<< Don't do this please

-16 1/2 units away

ehidna [41]4 years ago

7 0

Answer:

16 1/2

Step-by-step explanation:

find the absolute value of both and add them, there's you answer

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Write the equation of the line that passes through the point (3,5) and is perpendicular to the line y=3.

3241004551 [841]

Answer:

x = 3

Step-by-step explanation:

y = 3 is the equation of a horizontal line parallel to the x- axis.

A line perpendicular to it must therefore be a vertical line parallel to the y- axis with equation

x = c

where c is the value of the x- coordinates the line passes through.

The line passes through (3, 5) with x- coordinate 3 , thus

x = 3 ← equation of perpendicular line

6 0

4 years ago

A student studying for a vocabulary test knows the meanings of 16 words from a list of 26 words. If the test contains 10 words f

gayaneshka [121]

To get the probability that at least 8 of the words on the test are words that students know we need to do the following calculations.

<span>=[C(16,8)*C(10,2) + C(16,9)*C(10,1) + C(16,10)*C(10,0)] / C(26,10)
</span>
=0.132

4 0

3 years ago

Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

4 years ago

Find the following rates. Round your answer to the nearest hundredth. a. ? % of 75 = 5 b. ? % of 28 = 140 c. ? % of 100 = 40 d.

Nimfa-mama [501]

A.15 b.500 c.40 d.7.5 yeah, not to confident but I think it's correct.

5 0

3 years ago

Evaluate 6−(-9)/3*10

Sever21 [200]

15/30=1/2
The answer is B. 1/2

3 0

3 years ago