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pishuonlain [190]
3 years ago
13

Convert 32505 into equivalent number with base 5​

Mathematics
1 answer:
velikii [3]3 years ago
6 0

1s -0

5s- 1

25s- 0

125s- 0

625s- 2

3125s- 0

15625s- 2

2020010. I think this is right but would like so confirmation, just taught myself this!

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Hey how to do this and what the answer​
frez [133]

Answer:

5x + y - 4 = 0

Step-by-step explanation:

When we are given two points and are asked to find the equation of the line we use the two - point form.

Two - point form: $ \frac{y - y_1}{y_2 - y_1} = \frac{x - x_1}{x_2 - x_1} $.

where: $ (x_1,y_1) $ and $ (x_2,y_2) $ are the two points on the line.

Given the two points are: (5,21) and (-5,-29).

Substituting in the two point form:

⇒  $ \frac{y - 21}{-29 - 21} = \frac{x - 5}{-5 -5} $

$ \implies \frac{y - 21}{-50} = \frac{x - 5}{-10} $

$ \implies y - 21 = 5x - 25 $

⇒                              5x + y - 4 = 0

8 0
3 years ago
Jane will draw one card from the regular deck of 52 cards. In how many ways can she choose a jack or a black card?
elena-s [515]

Answer:

28

Step-by-step explanation:

In a regular 52 card deck, 26 are black (clubs or spades).  Additionally, there are two red jacks (diamonds and hearts).  This equals 28/52.  As a probability, it would be 28/52=14/26=7/13.  This could also be expressed as a percentage or decimal.  0.538 or 53.8%.  But the question asks <em>how many ways</em> can she choose a jack or black card, so I’m assuming they don’t want the probability, just the number, which is 28.

3 0
3 years ago
Read 2 more answers
John sold a car for 60,000 dollars and made a profit of 20%.what is the cost price of the car​
zhannawk [14.2K]

Answer:

72,000

Step-by-step explanation:

20% of 60,000 = 12,000

60,000 + 12,000 = 72,000

Chow,...!

7 0
3 years ago
Giselle bought a dress for $35 and three t-shirts. She used a coupon for $2.50 off each t-shirt. The total cost can be modeled b
aniked [119]
It’s represents the coupon for each shirt being taken on the price of each shirt
3 0
3 years ago
Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
Vinil7 [7]

Answer:

a)

X[bar]_A= 71.8cm

X[bar]_B= 72cm

b)

M.A.D._A= 8.16cm

M.A.D._B= 5.4cm

c) The data set for Soil A is more variable.

Step-by-step explanation:

Hello!

The data in the stem-and-leaf plots show the heights in cm of Teddy Bear sunflowers grown in two different types of soil (A and B)

To read the data shown in the plots, remember that the first digit of the number is shown in the stem and the second digit is placed in the leaves.

The two data sets, in this case, are arranged in a "back to back" stem plot, which allows you to compare both distributions. In this type of graph, there is one single stem in the middle, shared by both samples, and the leaves are placed to its left and right of it corresponds to the observations of each one of them.

Since the stem is shared by both samples, there can be observations made only in one of the samples. For example in the first row, the stem value is 5, for the "Soil A" sample there is no leaf, this means that there was no plant of 50 ≤ X < 60 but for "Soil B" there was one observation of 59 cm.

X represents the variable of interest, as said before, the height of the Teddy Bear sunflowers.

a) To calculate the average or mean of a data set you have to add all observations of the sample and divide it by the number of observations:

X[bar]= ∑X/n

For soil A

Observations:

61, 61, 62, 65, 70, 71, 75, 81, 82, 90

The total of observations is n_A= 10

∑X_A= 61 + 61 + 62 + 65 + 70 + 71 + 75 + 81 + 82 + 90= 718

X[bar]_A= ∑X_A/n_A= 218/10= 71.8cm

For Soil B

Observations:

59, 63, 69, 70, 72, 73, 76, 77, 78, 83

The total of observations is n_B= 10

∑X_B= 59 + 63 + 69 + 70 + 72 + 73 + 76 + 77 + 78 + 83= 720

X[bar]_B= ∑X_B/n_B= 720/10= 72cm

b) The mean absolute deviation is the average of the absolute deviations of the sample. It is a summary of the sample's dispersion, meaning the greater its value, the greater the sample dispersion.

To calculate the mean absolute dispersion you have to:

1) Find the mean of the sample (done in the previous item)

2) Calculate the absolute difference of each observation and the sample mean |X-X[bar]|

3) Add all absolute differences

4) Divide the summation by the number of observations (sample size,n)

For Soil A

1) X[bar]_A= 71.8cm

2) Absolute differences |X_A-X[bar]_{A}|

|61-71.8|= 10.8

|61-71.8|= 10.8

|62-71.8|= 9.8

|65-71.8|= 6.8

|70-71.8|= 1.8

|71-71.8|= 0.8

|75-71.8|= 3.2

|81-71.8|= 9.2

|82-71.8|= 10.2

|90-71.8|= 18.2

3) Summation of all absolute differences

∑|X_A-X[bar]_A|= 10.8 + 10.8 + 9.8 + 6.8 + 1.8 + 0.8 + 3.2 + 9.2 + 10.2 + 18.2= 81.6

4) M.A.D._A=∑|X_A-X[bar]_A|/n_A= 81.6/10= 8.16cm

For Soil B

1) X[bar]_B= 72cm

2) Absolute differences |X_B-X[bar]_B|

|59-72|= 13

|63-72|= 9

|69-72|= 3

|70-72|= 2

|72-72|= 0

|73-72|= 1

|76-72|= 4

|77-72|= 5

|78-72|= 6

|83-72|= 11

3) Summation of all absolute differences

∑ |X_B-X[bar]_B|= 13 + 9 + 3 + 2 + 0 + 1 + 4 + 5 + 6 + 11= 54

4) M.A.D._B=∑ |X_B-X[bar]_B|/n_B= 54/10= 5.4cm

c)

If you compare both calculated mean absolute deviations, you can see M.A.D._A > M.A.D._B. As said before, the M.A.D. summary of the sample's dispersion. The greater value obtained for "Soil A" indicates this sample has greater variability.

I hope this helps!

7 0
3 years ago
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