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Artyom0805 [142]
3 years ago
11

Whats the gcf of 44c^3,22c^3 and 11c^4

Mathematics
2 answers:
MA_775_DIABLO [31]3 years ago
8 0

Answer:

44c^3,22c^3 and 11c^4

11c^3

stepan [7]3 years ago
5 0
11c^3 your welcome if this helped :)
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ILL MARK U BRILLIANT PLEASE I NEED HELP
ahrayia [7]

Answer:

table, graph or equation

8 0
3 years ago
Can someone plz help me
Illusion [34]
First rectangle:
Has 3 cubes in each 5 layers, and imagine it, so we have all dimension needed which is:
l=3 unit
w=1 unit
h=5 unit.
V=l×w×h
V=3×1×5
V=15 cubic inches.

Second rectangular:
Doing the same like that to get:
l=5 unit
w=1 unit
h=3 unit
V=15 cubic inches. As a result, there are no prism that are greater to each other, which mean that they have the same volume of 15 cubic inches. Hope it help!
6 0
3 years ago
Which of the point-slope equations below is correct for the line that passes through points (5,6) and (1,1)?
kherson [118]
It's y-6=5/4(x-5) which is C
6 0
3 years ago
Select the equation in slope-intercept form that is equivalent to: 4x + 3y = 12
sattari [20]

Answer:

y = -4/3x +4

Step-by-step explanation:

y= mx+b

solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

Let's solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

3y / 3 =-4x +12 /3

y = -4/3x +4

hopes this helps you out

5 0
3 years ago
Identify the perimeter and area of a square with diagonal length 11in. Give your answer in simplest radical form. HELP PLEASE!!
Nataliya [291]

Answer:

  • Perimeter = 22*sqrt(2)
  • Area = 60.5 inches
  • D

Step-by-step explanation:

Remark

You need 2 facts.

  1. A square has 4 equal sides.
  2. It contains (by definition) 1 right angle but since we are not including and statement about parallel sides, it needs 4 right angles.

That means you can use the Pythagorean Theorem.

If one side of a square is a then the 1 after it is a as well.

Formula

  • a^2 + a^2 = c^2
  • 2a^2 = c^2

Givens

  • c = 11

Solution

  • 2a^2 = 11^2
  • 2a^2 = 121                    Divide by 2
  • a^2 = 121/2                  Take the square root of both sides
  • sqrt(a^2) = sqr(121/2)    
  • a = 11/sqrt(2)                Rationalize the denominator
  • a = 11 * sqrt(2)/[sqrt(2) * sqrt(2)]
  • a = 11 * sqrt(2) / 2

<em><u>Perimeter</u></em>

P = 4s

  • P = 4*11*sqrt(2)/2
  • P = 44*sqrt(2)/2
  • P = 22*sqrt(2)

You don't need the area. The answer is D

<em><u>Area</u></em>

  • Area = s^2
  • Area = (11*sqrt(2)/2 ) ^2
  • Area = 121 * 2 / 4
  • Area = 60.5


8 0
3 years ago
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