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zaharov [31]
3 years ago
10

1) -1 = x – 5 2) -5x + 2 = 17 PLS ANSWER PLS PLS PLS

Mathematics
1 answer:
Ede4ka [16]3 years ago
8 0
Are you trying to do substitution or elimination?
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The volume of sphere is increaseing
Artemon [7]

Volume of a sphere:

<em>V</em> = 4/3 <em>π</em> <em>r</em> ³

Differentiate <em>V</em> with respect to time <em>t</em> :

d<em>V</em>/d<em>t</em> = 4<em>π</em> <em>r</em> ² d<em>r</em>/d<em>t</em>

Surface area of a sphere:

<em>A</em> = 4<em>π</em> <em>r</em> ²

Differentiate <em>A</em> with respect to <em>t</em> :

d<em>A</em>/d<em>t</em> = 8<em>π</em> <em>r</em> d<em>r</em>/d<em>t</em>

<em />

You're given that the volume is increasing at a constant rate, d<em>V</em>/d<em>t</em> = 10 cm³/s, so

10 cm³/s = 4<em>π</em> <em>r</em> ² d<em>r</em>/d<em>t</em>

Solve for d<em>r</em>/d<em>t</em> (the rate of change of the sphere's radius):

d<em>r</em>/d<em>t</em> = 5/(2<em>π</em> <em>r</em> ²) cm³/s

Substitute this into the equation for d<em>A</em>/d<em>t</em> :

d<em>A</em>/d<em>t</em> = 8<em>π</em> <em>r</em> (5/(2<em>π</em> <em>r</em> ²) cm³/s)

d<em>A</em>/d<em>t</em> = 20/<em>r</em> cm³/s

At the moment the radius is <em>r</em> = 5 cm, the surface area is increasing at a rate of

d<em>A</em>/d<em>t</em> = 20/(5 cm) cm³/s = 4 cm²/s

When the surface area is increasing at a rate of d<em>A</em>/d<em>t</em> = 2 cm²/s, the radius <em>r</em> is such that

2 cm²/s = 20/<em>r</em> cm³/s

which happens when the radius is

<em>r</em> = 20/2 (cm³/s) / (cm²/s) = 10 cm

4 0
3 years ago
What is the answer to this question ?
Arisa [49]

Answer:

4

Step-by-step explanation:

h(7)= 7²-1= 49-1= 48

f(h(7))= 48/3 -12

= 16-12

= 4

7 0
4 years ago
Which figure shows an example of symmetry?
damaskus [11]

Answer:

It looks like B would be the correct answer.

Step-by-step explanation:

Hope this helps:)

4 0
3 years ago
Simplify.<br><br> 8(12 - p)<br><br> 20 - (8+p)<br> 96 - 8p<br> 96 - p<br> 96p
Romashka [77]

<em>So</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>C</em>

<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em>

<em>Hope </em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em> </em><em>.</em><em>.</em>

6 0
3 years ago
Find all values of x in the interval [0, 2π] that satisfy the equation. <br><br>6sin²(x) = 3
34kurt

Answer:

The solutions are π/4, 3π/4,5π/4,7π/4

Step-by-step explanation:

The given equation is

6sin²(x) = 3

Divide by 6 to get:

{ \sin}^{2} (x) =  \frac{1}{2}

This implies that;

\sin(x) = \pm  \frac{ \sqrt{2} }{2}

If

\sin(x) = \frac{ \sqrt{2} }{2}

x =  \frac{\pi}{4}

in the first quadrant

x =  \frac{3\pi}{4}

in the second quadrant.

If

\sin(x) = -  \frac{ \sqrt{2} }{2}

x =  \frac{5\pi}{4}

in the third quadrant

x =  \frac{7\pi}{4}

5 0
3 years ago
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