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3 years ago

8

What is the rectangle area

2 answers:

skelet666 [1.2K]3 years ago

4 0

The formula for area of a rectangle = length x width

Just insert the values and multiply.

pentagon [3]3 years ago

3 0

Length times the width

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WHAT ARE THE X AND Y INTERCEPTS FOR THIS?? <br><br>PLEASE ANSWERRRRR

valentina_108 [34]

Answer:

Y-intercept = 0.4

X-intercept = 0.3

Step-by-step explanation:

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3 years ago

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E^(8x)+e^(-x) find the interval on which f is increasing

saveliy_v [14]

Assuming ya mean
$f(x)=e^{8x}+e^{-x}$
take derivitive
remember dy/dx e^x=e^x
also the chain rule

so
$f'(x)=8e^{8x}+-1e^{-x}$
find where it equals 0
$0=8e^{8x}+-e^{-x}$
$e^{-x}=8e^{8x}$
multiply both sides by e^x
$1=8e^{9x}$
divide both sides by 8
$\frac{1}{8}=e^{9x}$
take ln of both sides
$ln(\frac{1}{8})=ln(e^{9x})$
$ln(\frac{1}{8})=9x$
divide both sides by 9
$\frac{ln(\frac{1}{8})}{9}=x$

x≈-1/5
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f'(0)>0

so it is increasing from x to infinity

the interval it is increasing on is $(\frac{ln(\frac{1}{8})}{9}, \infty)$

6 0

3 years ago

Determine the intercepts of the line. 4x-1=3y+54x−1=3y+54, x, minus, 1, equals, 3, y, plus, 5 xxx-intercept: \Big((left parenthe

earnstyle [38]

Answer:

The intercepts $(x,y) = (\frac{3}{2},-2)$

Step-by-step explanation:

Given:

$4x-1=3y+5$

Required

Determine the intercepts

The equation is a linear equation and the intercepts of the equation is calculated as thus;

For x intercepts; substitute 0 for y

$4x-1=3y+5$

$4x-1=3(0)+5$

$4x-1=0 + 5$

$4x-1=5$

Add 1 to both sides

$4x-1 + 1=5 + 1$

$4x = 6$

Divide both sides by 4

$\frac{4x}{4} = \frac{6}{4}$

$x = \frac{6}{4}$

Simplify fraction to lowest term

$x = \frac{3}{2}$

For y intercept, substitute 0 for x

$4x-1=3y+5$

$4(0)-1=3y+5$

$0 - 1 = 3y + 5$

$-1 = 3y + 5$

Subtract 5 from both sides

$-5 - 1 = 3y + 5 - 5$

$-6 = 3y$

Divide both sides by 3

$\frac{-6}{3} = \frac{3y}{3}$

$-2 = y$

Reorder

$y = -2$

Hence, the intercepts $(x,y) = (\frac{3}{2},-2)$

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3 years ago

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