I'm guessing the purpose of this exercise is to find the average value of
over the region
,
![D=\left\{(x,y)\mid (x,y)\in[-\pi,\pi]^2\right\}](https://tex.z-dn.net/?f=D%3D%5Cleft%5C%7B%28x%2Cy%29%5Cmid%20%28x%2Cy%29%5Cin%5B-%5Cpi%2C%5Cpi%5D%5E2%5Cright%5C%7D)
which is

The denominator is the measure (area) of
, which is easy to compute:

Not to be confused with the integral in the numerator:

but this integral is difficult to compute, hence the inequalities. We have




Answer:
3
Step-by-step explanation:
V=πr²h/3 = π3²·15/3 = 141.37167
-hope it helps
the slope intercept form is y=mx+b
since the line intersects at (0,3) b= 3
since the slope is 0 m= 0
so the equation would be y=0x+3 or y=3
Answer:
B. x^2 - 64 = 0
Step-by-step explanation:
A. x+10 = 33
B. x^2 - 64 = 0
C. Y-776
D. y = 4x + 6
A quadratic has an term with a power of two
Answer:
Step-by-step explanation:
<u>We know that:</u>
- Slope Formula = y₂ - y₁/x₂ - x₁
<u>Solution:</u>
- y₂ - y₁/x₂ - x₁ = -4 - 4/4 - 4
- => -8/0 = undefined
Since the slope of the line is un-defined, the line is vertical. Please look at my graph to understand better.