Which of the following is the domainof the given relation?{(-6, 3), (-4 ,5), (0, 0)}A {0, 4, -6}B {0, 3, 5)C {3, 4, 0}D {-6, -4,
Bas_tet [7]
The domain is the input, which is the x value in the relation (x, y)
Hence the domain in the given relation {(-6, 3), (-4 ,5), (0, 0) is :
{-6, -4, 0}
No, all linear pairs are supplementary but all supplementary angles are not linear pairs.
Answer:
D
Step-by-step explanation:
Answer:
well, when you are factoring you can always go back an check your work.
Step-by-step explanation: sorry i dont know if this is what you meant
Step 1 : Setting up the problem
Write the coefficients of the dividend in the same order. For missing terms, enter the co-efficient as zero. Set the divisor equal to zero and use that number in the division box.
The problem now looks as follows:
-1 | 12 5 3 0 -5
Step 2 : Bring down the first co-efficient and write it in the bottom row.
-1 | 12 5 3 0 -5
______________________ 12
Step 3 : Multiply the first coefficient with the divisor and enter the value below
the next co-efficient. Add the two and write the value in the bottom row.
-1 | 12 5 3 0 -5
_____-12_______________ 12 -7
Step 4 : Repeat Step 3 for rest of the coefficients as well:
-1 | 12 5 3 0 -5
____________7 ___________ 12 -7 10
-1 | 12 5 3 0 -5 ______________ -10______ 12 -7 10 -10
-1 | 12 5 3 0 -5 ____________________ 10_ 12 -7 10 -10 5
The last row now represents the quotient coefficients and the remainder. Co-efficients of Quotient are written one power less than their original power and the remainder is written as a fraction.
Answer :12x^3-7x^2+10x-10+5/(x+1) where the last term denotes the remainder and the rest is the quotient.
