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posledela
3 years ago
12

A recipe for a cake calls for 3 cups of flour. Tyler accidentally put in 4 cups. How many

Mathematics
2 answers:
Vladimir [108]3 years ago
8 0

Answer:

he put in one extra cup:)

Step-by-step explanation:

andre [41]3 years ago
7 0
He put in 1 extra cup because the recipe only needed 3. 4-3=1.
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Show your mastery of equivalent and simplifying fractions by using the sketchpad below to write the fraction
Sphinxa [80]
Answer: 2/3 (two thirds)

Explanation: Divide both denominator and numerator by the common factor of fourteen
3 0
2 years ago
When using the Distance Formula, the solution is the perimeter of a polygon.<br> true or false?
natali 33 [55]

Answer:

false

Step-by-step explanation:

When solving the distance formula it is the distance from one point to another. If you had a rectangle and used the distance formula from each point then you would have a perimeter

5 0
3 years ago
A shipment of 50 precision parts including 4 that are defective is sent to an assembly plant. The quality control division selec
natali 33 [55]

Answer:

0.3968 = 39.68% probability this shipment passes inspection.

Step-by-step explanation:

The parts are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

In this question:

50 parts means that N = 50

4 defective means that k = 4

10 are chosen, which means that n = 10

What is the probability this shipment passes inspection?

Probability that none is defective, so:

P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}

P(X = 0) = h(0,50,10,4) = \frac{C_{4,0}*C_{46,10}}{C_{50,10}} = 0.3968

0.3968 = 39.68% probability this shipment passes inspection.

6 0
2 years ago
A cube with side length 4 centimeters is 25% full of sand. What is the volume of sand
earnstyle [38]
First, find the volume of the whole cube
Volume of cube = 4 x 4 x 4 = 64 cm³

The volume of sand is 25% of the volume of cube so,
Volume of sand = 25/100 x 64 = 16 cm³
4 0
2 years ago
The average amount of time that students use computers at a university computer center is 36 minutes with a standard deviation o
frosja888 [35]

Answer:

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 36, \sigma = 5

The first step to solve this question is finding the proportion of students which use the computer more than 40 minutes, which is 1 subtracted by the pvalue of Z when X = 40. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{40 - 36}{5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

1 - 0.7881 = 0.2119

So 21.19% of the students use the computer for longer than 40 minutes.

Out of 10000

0.2119*10000 = 2119

2119 students use the computer for more than 40 minutes. This number is higher than the threshold estabilished of 2000, so yes, the computer center should purchase the new computers.

8 0
3 years ago
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