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ira [324]
3 years ago
8

Expression A: 2x+ 2 Expression B: 1 + 2x + 1 Which statement can be used to show that these expressions are equivalent? A. Each

expression includes the term 2x. B. 2x + 2 can be rewritten as 1 + 2x + 1 using the distributive property C. Both expressions involve addition D. The expressions name the same number regardless of the value of x.​
Mathematics
1 answer:
aliina [53]3 years ago
3 0

Answer:

C. Both expressions involves addition.

Step-by-step explanation:

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Free_Kalibri [48]
2/5 is the answer unless your multiplying
6 0
3 years ago
Question 1 (Multiple Choice Worth 4 points)
VLD [36.1K]

Answer:

In the first expression:

(5^3)^-4 = 5^-12

Step-by-step explanation:

4 0
3 years ago
Hello, Can someone please explain on how to do this? thank you!
Marrrta [24]
Steps:

1) determine the domain

2) determine the extreme limits of the function

3) determine critical points (where the derivative is zero)

4) determine the intercepts with the axis

5) do a table

6) put the data on a system of coordinates

7) graph: join the points with the best smooth curve

Solution:

1) domain

The logarithmic function is defined for positive real numbers, then you need to state x - 3 > 0

=> x > 3 <-------- domain

2) extreme limits of the function

Limit log (x - 3) when x → ∞ = ∞

Limit log (x - 3) when x → 3+ = - ∞ => the line x = 3 is a vertical asymptote

3) critical points

dy / dx = 0 => 1 / x - 3 which is never true, so there are not critical points (not relative maxima or minima)

4) determine the intercepts with the axis

x-intercept: y = 0 => log (x - 3) = 0 => x - 3 = 1 => x = 4

y-intercept: The function never intercepts the y-axis because x cannot not be 0.

5) do a table

 x                          y = log (x - 3)

limit x → 3+            - ∞

3.000000001        log (3.000000001 -3) = -9

3.0001                  log (3.0001 - 3) = - 4

3.1                       log (3.1 - 3) = - 1

4                          log (4 - 3) = 0

13                       log (13 - 3) = 1

103                     log (103 - 3) = 10

lim x → ∞             ∞

Now, with all that information you can graph the function: put the data on the coordinate system and join the points with a smooth curve.
7 0
3 years ago
Read 2 more answers
Can someone help me with this
stepan [7]

Answer:

hello i dont know

Step-by-step explanation:

3 0
2 years ago
-/2 points
Rom4ik [11]

Answer:

Part 1) The domain of the quadratic function is the interval  (-∞,∞)

Part 2) The range is the interval  (-∞,1]

Step-by-step explanation:

we have

f(x)=-x^2+14x-48

This is a quadratic equation (vertical parabola) open downward (the leading coefficient is negative)

step 1

Find the domain

The domain of a function is the set of all possible values of x

The domain of the quadratic function is the interval

(-∞,∞)

All real numbers

step 2

Find the range

The range of a function is the complete set of all possible resulting values of y, after we have substituted the domain.

we have a vertical parabola open downward

The vertex is a maximum

Let

(h,k) the vertex of the parabola

so

The range is the interval

(-∞,k]

Find the vertex

f(x)=-x^2+14x-48

Factor -1 the leading coefficient

f(x)=-(x^2-14x)-48

Complete the square

f(x)=-(x^2-14x+49)-48+49

f(x)=-(x^2-14x+49)+1

Rewrite as perfect squares

f(x)=-(x-7)^2+1

The vertex is the point (7,1)

therefore

The range is the interval

(-∞,1]

6 0
3 years ago
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