Hello, I need Help Please What is the Descending Order 219746, 612191, 194937

Mathematics

1 answer:

jolli1 [7]2 years ago

7 0

Answer:

124679 111269 134788

Step-by-step explanation:

this is the answer

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Which of the following is equal to <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B1%7D%7B5%5E2%7D%20%20" id="TexFormula1" title=

Elza [17]

Immediately omit the negative possible answer. Since 5^2 = 25, 1/5^2 = 1/25.

8 0

3 years ago

Write the equation Y=mx+b Not just the rate of change

Andreas93 [3]

Answer:

y=2/5x+8/5

Step-by-step explanation:

so say you plot a graph of rain against the hours the gradient would be the rate of change and the information given as your points and the gradient

now to get an equation of a straight line use one of your points eg(1,2) and the gradient or rate of change mine was 0.4

8 0

2 years ago

PLEASEE HELP ANYONE

Diano4ka-milaya [45]

There are two blue marbles so you have a 2/8 probability of drawing a blue marble on each draw since the marble is replaced after the first draw. 2/8 can be simplified to be 1/4 and then converted to be 0.25 per draw. 0.25 plus 0.25 equals 0.5. Since we are dealing with percentages multiply 0.5 x 100 which equals 50. Now take 50 and divided by the total number of marbles in the bag which is 8. 50 divided by 8 equals 6.25. So it would be about 6%.

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3 years ago

What is the solution to 31|-3x + 9|=-18

Kisachek [45]

Answer:

No solutions

Step-by-step explanation:

31 times any positive number cannot be a negative number.

8 0

2 years ago

Sara is working on a Geometry problem in her Algebra class. The problem requires Sara to use the two quadrilaterals below to ans

zloy xaker [14]

Part A:

Given a square with sides 6 and x + 4. Also, given a rectangle with sides 2 and 3x + 4

The perimeter of the square is given by 4(x + 4) = 4x + 16

The area of the rectangle is given by 2(2) + 2(3x + 4) = 4 + 6x + 8 = 6x + 12

For the perimeters to be the same

4x + 16 = 6x + 12
4x - 6x = 12 - 16
-2x = -4
x = -4 / -2 = 2

The value of x that makes the <span>perimeters of the quadrilaterals the same is 2.

Part B:

The area of the square is given by

$Area=(x+4)^2=x^2+8x+16$

The area of the rectangle is given by 2(3x + 4) = 6x + 8

For the areas to be the same

$x^2+8x+16=6x+8 \\ \\ \Rightarrow x^2+8x-6x+16-8=0 \\ \\ \Rightarrow x^2+2x+8=0 \\ \\ \Rightarrow x= \frac{-2\pm\sqrt{2^2-4(8)}}{2} \\ \\ = \frac{-2\pm\sqrt{4-32}}{2} = \frac{-2\pm\sqrt{-28}}{2} \\ \\ = \frac{-2\pm2i\sqrt{7}}{2} =-1\pm i\sqrt{7}$

Thus, there is no real value of x for which the area of the quadrilaterals will be the same.
</span>

7 0

3 years ago