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STatiana [176]
3 years ago
7

Simplify 4x + 8 = 0.1x + 3 +3.9x

Mathematics
1 answer:
julia-pushkina [17]3 years ago
7 0

Answer:

Step-by-step explanation:

4x+8=.1x+3+3.9x

4x+8=4x+3

No solution since the 4x's will cancel each other out

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Assume that females have pulse rates that are normally distributed with a mean of μ=73.0 beats per minute and a standard deviati
Gennadij [26K]

Answer:

a. the probability that her pulse rate is less than 76 beats per minute is 0.5948

b. If 25 adult females are randomly​ selected,  the probability that they have pulse rates with a mean less than 76 beats per minute is 0.8849

c.   D. Since the original population has a normal​ distribution, the distribution of sample means is a normal distribution for any sample size.

Step-by-step explanation:

Given that:

Mean μ =73.0

Standard deviation σ =12.5

a. If 1 adult female is randomly​ selected, find the probability that her pulse rate is less than 76 beats per minute.

Let X represent the random variable that is normally distributed with a mean of 73.0 beats per minute and a standard deviation of 12.5 beats per minute.

Then : X \sim N ( μ = 73.0 , σ = 12.5)

The probability that her pulse rate is less than 76 beats per minute can be computed as:

P(X < 76) = P(\dfrac{X-\mu}{\sigma}< \dfrac{X-\mu}{\sigma})

P(X < 76) = P(\dfrac{76-\mu}{\sigma}< \dfrac{76-73}{12.5})

P(X < 76) = P(Z< \dfrac{3}{12.5})

P(X < 76) = P(Z< 0.24)

From the standard normal distribution tables,

P(X < 76) = 0.5948

Therefore , the probability that her pulse rate is less than 76 beats per minute is 0.5948

b.  If 25 adult females are randomly​ selected, find the probability that they have pulse rates with a mean less than 76 beats per minute.

now; we have a sample size n = 25

The probability can now be calculated as follows:

P(\overline X < 76) = P(\dfrac{\overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{ \overline X-\mu}{\dfrac{\sigma}{\sqrt{n}}})

P( \overline X < 76) = P(\dfrac{76-\mu}{\dfrac{\sigma}{\sqrt{n}}}< \dfrac{76-73}{\dfrac{12.5}{\sqrt{25}}})

P( \overline X < 76) = P(Z< \dfrac{3}{\dfrac{12.5}{5}})

P( \overline X < 76) = P(Z< 1.2)

From the standard normal distribution tables,

P(\overline X < 76) = 0.8849

c. Why can the normal distribution be used in part​ (b), even though the sample size does not exceed​ 30?

In order to determine the probability in part (b);  the  normal distribution is perfect to be used here even when the sample size does not exceed 30.

Therefore option D is correct.

Since the original population has a normal distribution, the distribution of sample means is a normal distribution for any sample size.

5 0
3 years ago
Find the distance between the points ( – 9, – 4) and ( – 4,8).
Dmitriy789 [7]

Answer:

Distance=13\ units

Step-by-step explanation:

<u><em>Distance between two points:</em></u> Distance between two pints (x_1,y_1)\ and\ (x_2,y_2) is given by

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Distance between (-9,-4)\ and\ (-4,8).

d=\sqrt{(-4-(-9))^2+(8-(-4))^2}\\\\d=\sqrt{(-4+9)^2+(8+4)^2}\\\\d=\sqrt{(5)^2+(12)^2}=\sqrt{25+144}\\\\d=\sqrt{169}\\\\d=13

6 0
3 years ago
Here is Triangle A. Lin created a scaled copy of Triangle A with an area of 72 square units. a. How many times larger is the are
PSYCHO15rus [73]

Answer:

The answer is below

Step-by-step explanation:

a) Triangle A is attached in the image below.

The base of triangle A is 3 units and its height is 3 units. The area of a triangle  is given as:

Area = (1/2) × base × height

Area of triangle A = (1/2) × base × height = (1/2) × 3 × 3 = 4.5 unit²

Area of the scaled copy = 72 unit²

Ratio of area = Area of the scaled copy / Area of triangle A = 72 unit² / 4.5 unit² = 16

Hence the scaled copy area is 16 times larger than that of triangle A.

b) For the scaled copy:

Area of the scaled copy = (1/2) × base × height = 72 unit²

base × height = 144

Since the base and height are equal

base² = 144

base = 12, also height = 12

Base of scaled copy = 12 = 4 × base of triangle A

Therefore the scale factor used is 4

7 0
3 years ago
What would it be for this?
amm1812
It would be 41 because its m math
3 0
3 years ago
Find the missing length
Aleksandr [31]

25 is the answer/ third option

4 0
3 years ago
Read 2 more answers
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