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Nina [5.8K]
3 years ago
6

A child bus ticket costs $0.40 and an adult’s ticket costs $0.70. A group of 11 individuals pays $5.90 for their fare.

Mathematics
1 answer:
Fiesta28 [93]3 years ago
3 0
Let
A------------> <span>number of children
B------------> </span><span>number of adults

we know that
0.40A+0.70B=5.90--------------------------> equation 1
A+B=11------------> A=11-B----------------> equation 2

using a graph tool------------> to resolve the equations system
see the attached figure

the solution is 
A=6
B=5

the answer is 
A is bigger</span>

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The average adult horse needs two fith bale of hay each day to meet dietary requirements. A horse farm has 44 bales of hay. How
slava [35]

Answer: 110 horses

Step-by-step explanation:

Given

An average adult horse needs two fifth bale of hay

The farm has 44 bales of hay

Suppose n horses can be fed by the available bales of hay

So, we can  write

\Rightarrow n\times \dfrac{2}{5}=44\\\\\Rightarrow n=\dfrac{44\times 5}{2}=110\ \text{horses}

5 0
3 years ago
What are the variables for question 5, problem a, I don't quite understand.
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One variable is the amount of time it takes her to make a plate. The other variable is the amount of time it takes her to make a cup.
8 0
3 years ago
Which calculation should be used to calculate s9 for the arithmetic sequence an=3n-1
Ganezh [65]

Answer: Choice A

S9 = (9/2)*(2+26)

===============================================

The formula is

Sn = (n/2)*(a1+an)

where

Sn = sum of the first n terms (nth partial sum)

n = number of terms

a1 = first term

an = nth term

In this case,

n = 9

a1 = 2 (plug in n = 1 into the formula an = 3n-1 and simplify)

an = a9 = 26 (plug n = 9 into the formula an = 3n-1 and simplify)

So,

Sn = (n/2)*(a1+an)

S9 = (9/2)*(2+26)

will help us find the sum of the first 9 terms of this arithmetic sequence

7 0
2 years ago
Read 2 more answers
Solve for x and y in the system of equation<br>3x²+4y=17 <br>2x²+5y=2<br>I'll mark brainliest​
Novay_Z [31]

Answer:

x=\pm \sqrt{11} \\y=-4.

Step-by-step explanation:

\left \{ {{3x^2+4y=17} \atop {2x^2+5y=2}} \right. \\\\Then\\\\\left \{ {{2 \times (3x^2+4y)=2 \times 17} \atop {3\times(2x^2+5y)=3\times2}} \right. \\\\\left \{ {{6x^2+8y=34 \quad (1)} \atop {6x^2+15y=6\quad (2)}} \right.\\\\(1)-(2) \Rightarrow -7y=28 \Rightarrow y =-4.\\Since \: \:  2x^2+5y=2 \Rightarrow 2x^2=2-5y\\\Rightarrow 2x^2=2+20=22\\\Rightarrow x^2=22:2=11\\\Rightarrow x=\pm \sqrt{11}.

7 0
2 years ago
Solve the system of equations. −9y+4x−20=0−7y+16x−80=0\begin{aligned} &amp;-9y+4x - 20=0 \\\\ &amp;-7y+16x-80=0 \end{aligned} ​
gulaghasi [49]

Answer:

  • (x, y) = (5, 0)

Step-by-step explanation:

\begin{aligned} &-9y+4x - 20=0 \\ &-7y+16x-80=0 \end{aligned}

Subtract 4 times the first equation from the second:

  (-7y +16x -80) -4(-9y +4x -20) = (0) -4(0)

  29y = 0 . . . . . simplify

  y = 0 . . . . . . . .divide by 29

  4x -20 = 0 . . . . substitute 0 for y in the first equation

  x -5 = 0 . . . . . .divide by 4

  x = 5 . . . . . . . . add 5

The solution to this system is (x, y) = (5, 0).

7 0
3 years ago
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