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geniusboy [140]
3 years ago
8

What is the shortest bond type?

Chemistry
1 answer:
JulijaS [17]3 years ago
3 0
Double I think am sooooo sorry if you get it wrong
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The electrons determine chemical behavior
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What essential need of an organism jaw, arms, legs, teeth and eyes they serve to fill
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3 years ago
C6H12O6(s) + 6O2(g) --> 6H2O(g) + 6CO2(g)
vredina [299]
One
Balance the Equation.
This has been done for you or it is given. Anyway this step is finished, but it must always be done.

Two
Find the molar mass of C6H12O6
6C = 6 * 12 = 72
12H = 12*1 = 12
CO = 6 * 16 = 96
Mol Mass = 180 grams / mol

Three
Find the mols of C6H12O6
n = ???
Molar Mass = 180 grams / mol
given mass = 13.2 grams.

n = given mass / molar mass
n = 13.2 / 180
n = 0.07333333 mols.

Four
Find the mols CO2
1 mol C6H12O6 will produce 6 mols CO2
0.0733333 mols will produce x

1/0.073333 = 6/x Cross multiply
x = 0.073333 * 6
x = 0.4399 moles.

Five
Find the volume given the conditions for temperature and pressure are STP conditions.
PV = nRT
R = 0.082057 
n = 0.43999
P = 1 atmosphere
T = 0 + 273 = 273
V = ???
1 * V = 0.43999 * 082057 * 273
V = 10.2 L
Answer: B

Note if you give out Brainly awards I'd sure appreciate one. This was a lot of typing


8 0
3 years ago
What is the reaction of jack's tribe to ralph's talk of rescue?
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What book or story is it
8 0
4 years ago
A 0.50 molar aqueous solution of hydrochloric acid (HCl) flows into a process unit at 25°C and a rate of 1.25 m3/min. If the spe
Lerok [7]

Answer:

a) 18,23 kgHCl/m³

b) 0,38 kg HCl/s

c) 0,018 kgHCl/kgsolution

d) 8,75x10⁻³ molHCl/molH₂O

e) 0,010 kmolHCl/s

Explanation:

The HCl solution is 0,50 mol/L; it flows in a rate of 1,25 m³/min; Its density is 1,03 kg/L. HCl weights 36,46 g/mol

a) The HCl concentration in kg/m³ is:

\frac{0,50molHCl}{L}×\frac{36,46gHCl}{mol}×\frac{1kg}{1000g}×\frac{1000L}{1m^3}= <em>18,23 kg HCl/m³</em>

b) As you have a concentration of 18,23 kgHCl/m³

\frac{18,23 kgHCl}{m^3}×\frac{1,25m^3}{min}×\frac{1min}{60s} = <em>0,38 kg HCl/s</em>

c) The mass fraction in kgHCl/kgsolution is:

\frac{18,23kgHCl}{m^3}×\frac{1m^3}{1000L}×\frac{1L}{1,03kg} = <em>0,018 kgHCl/kgsolution</em>

d) Supposing L of solution are just of water:

\frac{0,50 moleHCl}{Lsolution}×\frac{1L}{1,03kg}×\frac{1kg}{1000g}×\frac{18,02gH_{2}O}{1mole}= <em>8,75x10⁻³ molHCl/molH₂O</em>

<em>e) </em>As the flow is 0,38kg HCl/s:

\frac{0,38 kg}{s}×\frac{1kmole}{36,46kgHCl}= <em>0,010 kmolHCl/s</em>

I hope it helps!

8 0
3 years ago
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