1%
Explanation:
The crust is the thinnest layer of the earth accounting for only 1% total volume of the planets.
Compositionally, the earth is divided into three layers which are the crust, mantle and the core.
- The crust is the outermost layer of the earth. It rich in silicate minerals. The rocks are classified into igneous, sedimentary and metamorphic rocks.
- The mantle takes up about 84% of the total volume of the earth. It is located in between the crust and the core. It is predominantly made up of ferro-magnesian silicate minerals.
- The cores accounts for slightly 15% of the volume of the earth. It is the center of our geoid shaped earth. It is rich in iron and nickel metals.
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NOOOO NO thats not true at all
<span>Esters can be shown in text as: RCOOR or (occasionally) ROCOR.</span>
<h3>Answer:</h3>
Number of Protons = 9
Number of Neutrons = 9
Number of Electrons = 10
<h3>Explanation:</h3>
Number of Protons:
The number of protons present in any atom are equal to the atomic number of that particular atom. Hence, as the atomic number of Fluorine is 9 therefore, it contains 9 protons.
Number Neutrons:
The number of neutrons present in atom are calculated as,
# of Neutrons = Atomic Mass - # of protons
As given,
Atomic Mass = 18
# of Protons = 9
So,
# of Neutrons = 18 - 9
# of Neutrons = 9
Number of Electrons:
As we know for a neutral atom the number of electrons are exactly equal to the number of protons present in its nucleus. So, for 9 protons in neutral Fluorine atom there must be 9 electrons. But, we are given with Fluoride Ion (i.e. F⁻) so it contains one extra electron hence, it contains the total of 10 electrons respectively.
Answer:
During the recharge process, the water infiltrates at the land's surface and flows through the unsaturated zone. It then crosses the water table and enters the groundwater system. Chloride (NaCl) is important and necessary because the sodium ions are held loosely and exchanged easily with calcium and magnesium ions.
Explanation:
Answer:
D) 0.86 M
Explanation:
Given that:
The rate constant, k = 6.7×10⁻⁴ s⁻¹
Initial concentration [A₀] = 1.33 M
Time = 644 s
Using integrated rate law for first order kinetics as:
![[A_t]=[A_0]e^{-kt}](https://tex.z-dn.net/?f=%5BA_t%5D%3D%5BA_0%5De%5E%7B-kt%7D)
Where,
![[A_t]](https://tex.z-dn.net/?f=%5BA_t%5D)
is the concentration at time t
So,
![[A_t]=1.33\times e^{-6.7\times 10^{-4}\times 644}](https://tex.z-dn.net/?f=%5BA_t%5D%3D1.33%5Ctimes%20e%5E%7B-6.7%5Ctimes%2010%5E%7B-4%7D%5Ctimes%20644%7D)
![[A_t]=0.86 M](https://tex.z-dn.net/?f=%5BA_t%5D%3D0.86%20M)
