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3 years ago

7

Which of the following is the correct Lewis structure for methane (CHA)?

1 answer:

Mkey [24]3 years ago

6 0

The correct lewis structure of methane(CH4)

C. H:C:H:H

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Which of the following pairs consists of a weak acid and a strong base?

Rudik [331]

A salt can either be a basic salt or acidic salt. An acidic salt contains a weak base and a strong acid. The acid and base undergoes a neutralization reaction to produce an acidic salt and water. A basic salt contains a weak acid and a strong base. The acid and base undergoes a neutralization reaction to produce a basic salt and water.

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3 years ago

Tell how you could distinguish between the pair of compounds by their infrared spectra: compound a ch3ch2ch2n(ch3)2 and compound

maksim [4K]

Answer:-

b. compound b will show an nh absorption while compound a will not.

Explanation:-

For compound B CH3CH2CH2NH2 there are two N-H bonds present. So it will show NH absorption.

But in compound A CH3CH2CH2N(CH3)2 there are no N-H bonds. So it will not show NH absorption.

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4 years ago

What is the amount of space occupied by a sample of matter

dusya [7]

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2 years ago

_____ are two or more elements that have been chemically combined. mixtures compounds atoms colloids

Ulleksa [173]

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4 years ago

Read 2 more answers

How many grams of testosterone, C19H28O2 (288.4 g/mol), must be dissolved in 299.0 grams of benzene to reduce the freezing point

iVinArrow [24]

Answer: 8.42 grams of testosterone

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=0.500^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant of benzene= $5.12^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (benzene)= 299.0 g = 0.299 kg

Molar mass of solute testosterone= 288.4 g/mol

Mass of solute testosterone added = ?

$0.500=1\times 5.12\times \frac{xg}{288.4 g/mol\times 0.299kg}$

$x=8.42g$

Thus 8.42 grams of testosterone must be dissolved in 299.0 grams of benzene to reduce the freezing point by 0.500°C.

8 0

4 years ago