Question

A circle with a center at (2,-3) passes through the point (-1,-8). Write the equation of the circle.

Answer 1

Answer: (x - 2)^2 + (y + 3)^2 = 34

Step-by-step explanation:

The basic equation for a circle is

(x - a)^2 + (y - b)^2 = r^2 where (a, b) is the centre of the circle

Using Pythagoras we can find r^2

r^2 = (2 - -1)^2 + (-3 - -8)^2

= 3^2 + 5^2

= 34

So the circle is (x - 2)^2 + (y - -3)^2 = 34