v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
Answer:
D. x=1
Step-by-step explanation:
Image can be rewritten as 3x + 6 = 9.
Solve for x.
3x +6 = 9
Isolate x by subtracting 6 from both sides.
3x = 3
Get rid of the 3 by dividing by 3 on both sides.
x = 1
Hope this helped.
Top boxes: | X | 1 | 2 | 3 |
bottom boxes: | Y=2X - 2 | 0 | 2 | 4 |
