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frez [133]
2 years ago
8

Please Helpppp Me User Interface Design ensures that the interface has elements that are easy to ________________. (Choose all t

hat apply)
Question 1 options:


a) access



b) understand



c) change location



d) remove



e) use to facilitate actions
Computers and Technology
1 answer:
kari74 [83]2 years ago
8 0

Answer:

understand is the answer

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Refer to the exhibit. A network security analyst is using the Follow TCP Stream feature in Wireshark to rebuild the TCP transact
Mnenie [13.5K]

Answer:

Binary file.

Explanation:

                           In this case, the network security analyst is using the Follow TCP Stream feature in Wireshark to rebuild the TCP transaction. However, the transaction data seems indecipherable. The explanation for this is that the TCP transaction file is a Binary File and because of this the network secuirty analyst is unable to decipher the transaction file.

                           The solution for this is to convert the binary file into text file which is human readable.

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Complete the sentence to identify advantages of top-down programming design. Choose all that apply.
yanalaym [24]

Answer:The original choice to write apply_fg so that it accepts function arguments is a good one, because it increases interoperability. When the callable arguments to apply_fg use a single protocol, we can easily exchange them: #include <functional> float log2(float); int a = apply_fg(5.Of, int b = apply_fg(3.14f,

Explanation:

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3 years ago
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What was the best Metal Gear Solid you enjoyed the most?​
kenny6666 [7]

My personal favorite is Metal gear solid 3: <em>Snake eater</em>.

7 0
3 years ago
Write a program that takes a point (x,y) from theuser and find where does the point lies. The pointcan
agasfer [191]

Answer:

C++ Program .

#include<bits/stdc++.h>

using namespace std;

int main()

{

int x,y;//declaring two variables x and y.

string s;//declaring string s..

cout<<"enter x and y"<<endl;

cin>>x>>y;//taking input of x and y..

if(x>=0 &&y>=0) //condition for 1st quadrant..

cout<<"the point lies in 1st Quadrant"<<endl;

else if(x<=0 &&y>=0)//condition for 2nd quadrant..

cout<<"the point lies in 2nd Quadrant"<<endl;

else if(x>=0 &&y<=0)//condition for 3rd quadrant..

cout<<"the point lies in 3rd Quadrant"<<endl;

else //else it is in  4th quadrant..

cout<<"the point lies in 4th Quadrant"<<endl;

cout<<"enter n to terminate the program"<<endl;

while(cin>>s)//if the user has not entered n the program will not terminate..

{

   if(s=="n")

   {

       cout<<"the program is terminated"<<endl;

       exit(0);

   }

   cout<<"you have not entered n please enter n to terminate the program<<endl;

}

}

Explanation:

The above written program is for telling the point lies in which quadrant.I am first declaring two variables x and y.Then after that taking input of x and y after that checking in which quadrant the point lies.

Taking input of the string s declared earlier for program termination the program will keep running until the user enters n.

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What are the choices?

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