So what you need to start with is taking the x from both sides as adding 12 to them. Then, you move the 27 over 4 decimals.
Answer:
Step-by-step explanation:
We have
square with sides <em>s = 3cm</em>
four triangles with base <em>b = 3cm</em> and height <em>h = 9cm</em>.
The formula of an area of a square:
The formula of an area of a triangle:
Substitute:
The Surface Area:
its actually 10 points
x^4 + 9x^3 + 15x^2 + 9x + 14
Split 15x^2 into 14x^2 + x^2
x^4 + 9x^3 + 14x^2 + x^2 + 9x + 14 factor as
x^2 [x^2 + 9x + 14 ] + 1 [ x^2 + 9x + 14 ] take out GCF
[ x^2 + 1 ] [ x^2 + 9x + 14 ]
[ x^2 + 1 ] [ x + 7 ] [ x + 2 ]
mark brainliest
Answer:
x = 4 sqrt(2)
Step-by-step explanation:
This is a right triangle so we can use trig functions
sin theta = opp/ hypotenuse
sin 45 = 4/x
Multiply x to each side
x sin 45 = 4/x *x
x sin 45 = 4
Divide each side by sin 45
x sin 45 / sin 45 = 4 /sin 45
x = 4/ sin 45
We know sin 45 = sqrt(2)/2
x = 4/ sqrt(2) /2
x = 8/ sqrt(2)
We do not leave a sqrt in the denominator so multiply by sqrt(2)/ sqrt(2)
x = 8/ sqrt(2) * sqrt(2)/sqrt(2)
x = 8 * sqrt(2) /2
x = 4 sqrt(2)
