I had two oranges, Bernice took two, how many do I have left?

Mathematics

1 answer:

Tpy6a [65]3 years ago

6 0

Answer:

0 Oranges

Step-by-step explanation:

If you had 2 oranges at the start, then your no good friend Bernice took 2 of them, you don't have any oranges left, so get back at him and steal his bannanas! That'll teach him!

You might be interested in

Simplify 1/3a+3/5-1/15+2/3a

Misha Larkins [42]

Answer: $\frac{15+8a}{15a}$

Step-by-step explanation:

$=\frac{1}{3a} +\frac{3}{5} -\frac{1}{15}+ \frac{2}{3a} \\= \frac{1}{3a} +\frac{8}{15} +\frac{2}{3a} \\=\frac{5+8a+10}{15a} \\=\frac{15+8a}{15a}$

7 0

1 year ago

Read 2 more answers

Whats 24/6- 4/2 whats the answer dawg

aleksandrvk [35]

Answer:

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Ursula tosses two six-sided number cubes and MULTIPLIES the numbers rolled. Which of these is a list of the outcomes of the two

Black_prince [1.1K]

Answer:

3,4,5,6,7,8

Step-by-step explanation:

sum of 2 with other possible numbers:

2+1, 2+2, 2+3, 2+4, 2+5, 2+6

3, 4, 5, 6, 7, 8

5 0

3 years ago

Find the indicated probability.

natka813 [3]

Answer:

C) 0.179

Step-by-step explanation:

Since the trials are independent, this is a binomial distribution:

Recall:

Binomial Distribution --> $P(k)={n\choose k}p^kq^{n-k}$
$P(k)$ denotes the probability of $k$ successes in $n$ independent trials
$p^k$ denotes the probability of success on each of $k$ trials
$q^{n-k}$ denotes the probability of failure on the remaining $n-k$ trials
${n\choose k}=\frac{n!}{(n-k)!k!}$ denotes all possible ways to choose $k$ things out of $n$ things