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3 years ago

[2x+4] -[-x+5 ]subtract linear expressions

Mathematics

1 answer:

Olin [163]3 years ago

6 0

(2x +4 ) - (x+5)

when we open the brackets the sign (-) will change to (+) so,

2x+4 - x-5

x+4-5

x-1

<h3>Hope this helps you mate </h3>

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Solve each equation. Round your answers to the nearest ten-thousandth. Please show work. Part 3A

Butoxors [25]

Answer:

19.

log9(5x^2 + 10) - log9(10) = 1

<=> log9((5x^2 + 10)/10) = log9(9)

<=> (5x^2 + 10)/10 = 9

<=> 5x^2 + 10 = 90

<=> 5x^2 = 80

<=> x^2 = 16

<=> x = +/- (4)

20.

log5(2x^2 + 4) + log5(3) = 2

<=> log5((2x^2 + 4) x 3) = log3(9)

<=> 6x^2 + 12 = 9

<=> 6x^2 = -3

=> No real x satisfies. ( x^2 always larger or equal to 0)

21.

log6(8) + log6(7 - 2x^2) = 2

<=> log6(8 x (7 - 2x^2)) = log6(36)

<=> 56 - 16x^2 = 36

<=> 16x^2 = 20

<=> x^2 = 5/4

<=> x = +/- sqrt(5/4)

Hope this helps!

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3 years ago

A triangle has two sides that measures 7 cm which of the following cannot be the measure of the third side

klasskru [66]

Any side that is greater than 7 + 7 = 14 will not make a triangle.

x > 14 will not create a triangle.

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2 years ago

Suppose that 7 female and 5 male applicants have been successfully screened for 5 positions. If the 5 positions are filled at ra

katen-ka-za [31]

Answer:

(a) 350

(b) 175

(d) 196

Step-by-step explanation:

Number of females = 7

Number of males = 5

Total ways of selecting r items from n items is

$^nC_r=\dfrac{n!}{r!(n-r)!}$

(a)

Total ways of selecting 3 females and 2 males.

$\text{Total ways}=^7C_3\times ^5C_2$

$\text{Total ways}=\dfrac{7!}{3!(7-3)!}\times \dfrac{5!}{2!(5-2)!}$

$\text{Total ways}=35\times 10$

$\text{Total ways}=350$

(b)

Total ways of selecting 4 females and 1 male.

$\text{Total ways}=^7C_4\times ^5C_1$

$\text{Total ways}=32\times 5$

$\text{Total ways}=175$

(c)

Total ways of selecting 5 females.

$\text{Total ways}=^7C_5\times ^5C_0$

$\text{Total ways}=21\times 1$

$\text{Total ways}=21$

(d)

Total ways of selecting at least 4 females.

Total ways = 4 females + 5 females

$\text{Total ways}=175+21$

$\text{Total ways}=196$

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3 years ago

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Mariana [72]

Answer:

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Step-by-step explanation:

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