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son4ous [18]
3 years ago
12

Solve the following equation algebraically. Shiw your work. 17=-13-8x

Mathematics
1 answer:
maxonik [38]3 years ago
8 0

17=13-8x

-13 . -13

4=8x

/8 .  /8

x=1/2 OR 0.5

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A gardener wants to fence a circular garden of diameter 21 m. Find the length of the rope he needs to purchase, if he makes 2 ro
djyliett [7]

Answer:

a). total length of rope=132 m

b). total cost of the rope=$528

Step-by-step explanation:

Step 1

To get the total length of rope needed to cover the circular garden twice, we express this as;

P=πD

where;

P=perimeter

π=pi

D=diameter

In our case;

π=22/7

D=21 m

replacing;

P=(22/7)×21=66 m

2×P=2×66=132 m

total length of rope=132 m

Step 2

The expression to calculate the total cost can be written as;

total cost=cost per meter length×total length of rope

where;

cost per meter=$4

total length of rope=132 m

replacing;

total cost=4×132=$528

total cost of the rope=$528

7 0
3 years ago
Simplify the expression. 4 + 5\3^2 - 2^2 <br> A) -3 <br> B) -5 <br> C) 5 <br> D) 9\5
DedPeter [7]

Answer:

D

Step-by-step explanation:

\frac{4+5}{3^{2}-2^{2}}=\frac{9}{9-4}\\\\=\frac{9}{5}

4 0
3 years ago
Can you please tell me if this is correct ?
pashok25 [27]

Answer:

(6*3) - 5

Step-by-step explanation:

The product of 6 & 3 = 6*3 = 18

5 less than 18 means the required number is 5 units smaller than 18. so you have to subtract from 18

18 - 5 = 13

13 is 5 less than 18

5 0
3 years ago
two sides of a triangle have the same length the thrid side measures 5m less than twice the common length the perimeter of the t
Vlad [161]
<span>Let x= measure of sides that have common length
then from "the third side measures 5m less than twice the common length."
2x-5= third side
.
Because they gave us the perimeter we have:
11 = x+x+2x-5</span><span>11 = 4x-5
16 = 4x
4 m = x
.
third side:
2x- 5 =2(4)-5 = 8-5= 3m</span>
Length answers:
4m, 4m, and 3m
7 0
4 years ago
A box contains 24 light bulbs of which 4 are defective
klio [65]
The awnser should be either 6 or 20
5 0
3 years ago
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