Answer:
A)
Step-by-step explanation:
the solution of a squared equation is
x = (-b ± sqrt(b² - 4ac)) / (2a)
in our case
a = 1
b = 8
c = 22
x = (-8 ± sqrt(64 - 88))/2 = (-8 ± sqrt(-24))/2 =
= (-8 ± sqrt(4×-6))/2 = (-8 ± 2×sqrt(-6))/2 =
= -4 ± sqrt(-6) = -4 ± i×sqrt(6)
9 if your in k12 this is the answer trust me i just took the test
Answer:
B -1/5
you have to follow pemdas first get rid of the parethase which leaves you with 2+3x+6x=-4x+8x+1 then you add what you can do then you get 2+9x=4x+1 then you subtract 2 from both sides and subtract 4x from both sides which leaves you with 5x=-1 then you divide 5 from both sides and get x=-1/5
Since the distance of MN is 31 and we have a distance of ML
of h -15 and LN of 2h – 8, therefore
ML + LN = h -15 + 2h – 8 = 31
h = 18
substituting the value of h to the expression for LN
obtaining
LN = 2h – 8
LN = 2(18) – 8
LN = 28
Therefore the length of the segment LN is 28 units
Answer:angle nkl is congruent to angle zwx
Step-by-step explanation: it is equal so it matches
