Answer:
R² = 0.964
Step-by-step explanation:
y = 1.9694x - 0.6122
R² = 0.964
Recall that variation of parameters is used to solve second-order ODEs of the form
<em>y''(t)</em> + <em>p(t)</em> <em>y'(t)</em> + <em>q(t)</em> <em>y(t)</em> = <em>f(t)</em>
so the first thing you need to do is divide both sides of your equation by <em>t</em> :
<em>y''</em> + (2<em>t</em> - 1)/<em>t</em> <em>y'</em> - 2/<em>t</em> <em>y</em> = 7<em>t</em>
<em />
You're looking for a solution of the form

where


and <em>W</em> denotes the Wronskian determinant.
Compute the Wronskian:

Then


The general solution to the ODE is

which simplifies somewhat to

Domain of

are the values of x for which 2x + 1 < 0
2x < -1
x < -1/2
Therefore, domain is all real numbers less than -1/2
Answer:
z = 155 ( second choice )
Step-by-step explanation:
x = 25
65 + 90 = 155
180 - 155 = 25 = x
180 - 25 = 155 = z
Answer:
Solution given:
Cos X=Adjacent/hypotenuse
Cos X=6.5/8.4
x=Cos-¹(6.5/8.4)
<u>x=39.3</u>°