Question

Q8. Look at the image.

Answer 1

Answer:

Option B

Step-by-step explanation:

Quadratic equation given in the question is,

$x^2+4x+2=0$

By comparing this equation with the standard quadratic equation,

$ax^2+bx+x=0$

$a=1,b=4$ and $c=2$

By using quadratic formula to get the roots of the given quadratic equation,

$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$

By substituting the values of a, b and c in the formula,

$x=\frac{-4\pm\sqrt{4^2-4(1)(2)}}{2(1)}$

$x=\frac{-4\pm\sqrt{16-8}}{2}$

$x=\frac{-4\pm\sqrt{8}}{2}$

$x=\frac{-4-\sqrt{8}}{2},\frac{-4+\sqrt{8}}{2}$

$x=-3.414,-0.5857$

$x=-3.41,-0.59$

Therefore, Option B will be the answer.