Given :
As a plane takes off it ascends at a 20 degree angle of elevation.
If the plane has been travelling at an average rate of 290 ft/s and continues to ascend at the same angle.
To Find :
How high is the plane after 10 seconds.
Solution :
Distance travelled by plane, D = 2900 ft.
Angle of elevation, Ф = 20°.
Height gained is given by :
H = 2900 × sin 20°
H = 991.86 ft.
Therefore, height of plane after 10 seconds is 991.86 ft.
Hence, this is the required solution.
Answer: the rate at which its altitude is changing is -47 ft/s
Step-by-step explanation:
Given that;
ds/dt = 45 mph = 45 × 5280/3600 = 66 ft/sec
no we have to determine dx/dt
so
cos∅ = dx/dt / ds/dt
cos45° = dx/dt / 66
dx/dt = 0.7071 × 66
dx/dt = 46.6686 ≈ 47 ft/s ( as altitude is decreasing, its negative - )
so the rate at which its altitude is changing is -47 ft/s
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