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3 years ago

5

A paper company needs to ship paper to a large printing business. The paper will be

1 answer:

slamgirl [31]3 years ago

3 0

45x+75y=1410 i hope this helps bc i’m pretty sure i’m learning the same thing but i hope this helps

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A rectangular cooler made of MycoFoam is 13 inches wide, 7 inches tall, and 7 inches long. what is its surface area?

yarga [219]

To find area u have to multiply the sides so it should be 7x7 or 13x7 it shouldnt be 13x7x7

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3 years ago

Help me please. solve for f (-2)

Naddika [18.5K]

Answer:

9

Step-by-step explanation:

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3 years ago

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Use the Associative Property of Addition to find the total of 4, 12, and 18 in two different ways.

Alex Ar [27]

4, 12, and 18 in two different ways

<span>(4 + 12) + 18 = 16 + 18 = 34

4 + (12 + 18) = 4 + 30 = 34

answer is B) </span><span>(4 + 12) + 18 = 16 + 18 = 34; 4 + (12 + 18) = 4 + 30 = 34 (second choice)</span>

6 0

3 years ago

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An equation is shown below:

IrinaK [193]

5(2x - 8) + 15 = -15
-15 -15 subtract 15 from each side
5(2x - 8) = -30
÷5 ÷5 divide both sides by 5
2x - 8 = -6
+8 +8 add 8 to each side
2x=2
÷2 ÷2 divide both sides by 3
x = 1

Checking:
5(2(1)-8) + 15 = -15
5(-6) + 15 = -15
-30 + 15 = -15
-15 = -15 Correct! x=1

7 0

4 years ago

Read 2 more answers

Determine the lengths of the sides of the rectangle using the given area. Give answers both exactly and

Degger [83]

Answer:

Part a) Exactly values

The width of the rectangle is $\frac{\sqrt{70}}{2}\ cm$

The length of the rectangle is $2\sqrt{70}\ cm$

Part b) Approximately values

The width of the rectangle is $4.2\ cm$

The length of the rectangle is $16.7\ cm$

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

The area of rectangle is equal to

$A=LW$

we have

$L=4x\ cm\\W=x\ cm$

substitute the values in the formula

$A=4x(x)$

$A=4x^2$

$A=70\ cm^2$

so

$70=4x^2$

Solve for x

Divide by 4 both sides

$\frac{70}{4}=x^2$

square root both sides

$x=(+/-)\frac{\sqrt{70}}{2}$

The solution is the positive value

$x=\frac{\sqrt{70}}{2}$

therefore

<em>Exactly values</em>

$L=4\sqrt{70}}{2}=2\sqrt{70}\ cm\\\\W=\frac{\sqrt{70}}{2}\ cm$

<em>Approximately values</em>

$L=4\sqrt{70}}{2}=16.7\ cm\\\\W=\frac{\sqrt{70}}{2}=4.2\ cm$

6 0

3 years ago