52x because there are approximately 52 weeks in a year.
You are gonna use the distributive property.
4(2.5g - 4) + 3(1.2g - 2)
So you are going to multiply 4 with everything inside the first set of parenthesis and your gonna multiply 3 with everything insides the second set of parenthesis.
4 x 2.5g - 4 x 4 + 3 x 1.2g - 3 x 2
10g - 16 + 3.6g - 6
You wanna combine like terms:
10 - 3.6g + 16 - 6
6.4g + 10
You answer is 6.4g + 10.
Hope this Helps!!
Use the equation of motion under gravity:-
s = 16t^2 where s is the distance and t = time
2063 = 16t^2
t^2 = 2063 / 16 = 128.94 s
t = sqrt 128.94 = 11. 4 seconds to the nearest tenth of a second
The corresponding homogeneous ODE has characteristic equation
with roots at
, thus admitting the characteristic solution

For the particular solution, assume one of the form



Substituting into the ODE gives



Then the general solution to this ODE is



Assume a solution of the form



Substituting into the ODE gives



so the solution is



Assume a solution of the form


Substituting into the ODE gives



so the solution is

Answer:
4
Step-by-step explanation:
44 ÷ 11 = 4