All categories

3 years ago

3. Andrea is buying snacks at the basketball game. The snacks are $2.25 apiece. She wants to buy 4

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

4 0

Answer:

D - No, the ordered pair (4,9) is a solution to this problem.

Step-by-step explanation:

If you plotted the number of snacks as the x-axis, and then the total cost of the snacks on the y-axis, you would be able to graph a line and see the cost of snacks based on the number purchased. If you were going to write an equation for this, it would be y=2.25x (or y = 2 1/4 x)

In this case, as each snack is the same price, the y-values for each x would be as such: (1, 2.25) <- one snack, $2.25;

(2, 4.5)

(3, 6.75)

(4, 9)

So that is why the ordered pair of (4,9) would be a solution to this problem.

Hope that makes sense!

You might be interested in

Which ordered pairs are solutions to the inequality x+3y≥−8?

Dima020 [189]

I think the answer would be b

6 0

3 years ago

Three friends have a total of 6 identical pencils, and each one has at least one pencil. In how many ways can this happen?

Lorico [155]

Answer:

Step-by-step explanation:

events are 1+1+4=6

1+2+3=6

1+3+2=6

1+4+1=6

2+1+3=6

2+2+2=6

2+3+1=6

3+1+2=6

3+2+1=6

4+1+1=6

total number of ways=10

7 0

3 years ago

Read 2 more answers

Suppose that the length of a side of a cube X is uniformly distributed in the interval 9

Nastasia [14]

Answer:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

Step-by-step explanation:

Given

$9 < x < 10$ --- interval

Required

The probability density of the volume of the cube

The volume of a cube is:

$v = x^3$

For a uniform distribution, we have:

$x \to U(a,b)$

and

$f(x) = \left \{ {{\frac{1}{b-a}\ a \le x \le b} \atop {0\ elsewhere}} \right.$

$9 < x < 10$ implies that:

$(a,b) = (9,10)$

So, we have:

$f(x) = \left \{ {{\frac{1}{10-9}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Solve

$f(x) = \left \{ {{\frac{1}{1}\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$

Recall that:

$v = x^3$

Make x the subject

$x = v^\frac{1}{3}$

So, the cumulative density is:

$F(x) = P(x < v^\frac{1}{3})$

$f(x) = \left \{ {{1\ 9 \le x \le 10} \atop {0\ elsewhere}} \right.$ becomes

$f(x) = \left \{ {{1\ 9 \le x \le v^\frac{1}{3} - 9} \atop {0\ elsewhere}} \right.$

The CDF is:

$F(x) = \int\limits^{v^\frac{1}{3}}_9 1\ dx$

Integrate

$F(x) = [v]\limits^{v^\frac{1}{3}}_9$

Expand

$F(x) = v^\frac{1}{3} - 9$

The density function of the volume F(v) is:

$F(v) = F'(x)$

Differentiate F(x) to give:

$F(x) = v^\frac{1}{3} - 9$

$F'(x) = \frac{1}{3}v^{\frac{1}{3}-1}$

$F'(x) = \frac{1}{3}v^{-\frac{2}{3}}$

$F(v) = \frac{1}{3}v^{-\frac{2}{3}}$

So:

$f(v) = \left \{ {{\frac{1}{3}v^{-\frac{2}{3}}\ 9^3 \le v \le 10^3} \atop {0, elsewhere}} \right.$

8 0

3 years ago

Neeeedddd Helpppp Plzzzzz

Nataly_w [17]

Answer:

Linear Angles

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

4 0

3 years ago

Read 2 more answers

This week, 300 tickets were sold to the school play. This is 120 percent of the number of tickets sold last week for the school

skad [1K]

Answer:

the awnser is 250 i took the test and got it correct

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers