Answer:
X = 89.92° or 90.08°
Step-by-step explanation:
The law of sines can be used to find the value of angle X:
sin(X)/26 = sin(67.38°)/24
sin(X) = (26/24)sin(67.38°) ≈ 0.99999901787
There are two values of X that have this sine:
X = arcsin(0.99999901787) ≈ 89.92°
X = 180° -arcsin(0.99999901787) ≈ 90.08°
There are two solutions: X = 89.92° or 90.08°.
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<em>Comment on the problem</em>
We suspect that the angle is supposed to be considered to be 90°. However, the given angle is reported to 2 decimal places, so we figure the requested angle should also be reported to 2 decimal places.
The lengths of the short side that correspond to the above angles are 10.03 and 9.97 units. If the short side were considered to be 10 units, the triangle would be a right triangle, and the larger acute angle would be ...
arcsin(24/26) ≈ 67.38014° . . . . rounds to 67.38°
This points up the difficulty of trying to use the Law of Sines on a triangle that is actually a right triangle.
Answer:
Step-by-step explanation:
Base on my own understanding what should be done is that three stacks will not work, because it wont be a symmetric arrangement and also one will be left out. So, two stacks of five each would be better and easy to carry. But the stacks should be arranged in such a manner that the lengths will be parallel to each other and not in-line which would increase the length making it comparatively very long. its easier to hold a (2*8.5,11,2*5=17,11,17) compact box, because it will be easy to carry a long and not heavy.
Answer:
35
Step-by-step explanation:
If is given the value -8 as it is the input then -->
y = -4(-8) + 3
Negative four times negative 8 is positive 32 so
y= 32 + 3
And 32 plus 3 is 35
121/100 is the answer. it cant be simplified anymore
Answer:
15) K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
Step-by-step explanation:
We are to find the derivative of the questions pointed out.
15) K(t) = 5(5^(t)) - 2(3^(t))
Using implicit differentiation, we have;
K'(t) = 5[5^(t)•In 5] - 2[3^(t)•In 3]
19) P(w) = 2e^(w) - (2^(w))/5
P'(w) = 2e^(w) - (1/5)[2^(w)•In 2]
20) Q(W) = 3w^(-2) + w^(-2/5) - w^(¼)
Q'(w) = -6w^(-2 - 1) + (-2/5)w^(-2/5 - 1) - ¼w^(¼ - 1)
Q'(w) = -6w^(-3) - (2/5)w^(-7/5) - ¼w^(-¾)
