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Nadya [2.5K]
3 years ago
14

2x - 8 X-3 4. What is the value of x? (a) 3 (c) 9 (b) 15 (d) 30 5 3

Mathematics
1 answer:
azamat3 years ago
5 0
I believe it’s 9 but unsure sorry
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Can you help me please
spin [16.1K]
It would be < and > ........


6 0
3 years ago
Read 2 more answers
The total cost of four movie tickets is $33.40. What is the cost of one ticket?
hjlf
The answer is 8.35. Have a nice day hope this helped!
3 0
3 years ago
Read 2 more answers
You can approximate e by substituting large values for ninto the expression
ratelena [41]

You can approximate e by substituting large values for (1 + 1/n)^n into the expression.

<h3>How to illustrate the expression?</h3>

It should be noted that an expression can simply be used to illustrate the information given in a data.

In this case, you can approximate e by substituting large values for (1 + 1/n)^n into the expression.

Learn more about expressions on:

brainly.com/question/723406

#SPJ1

8 0
2 years ago
A cone has a radius of 6 inches and a height of 9 inches. What is the volume of the cone?
mario62 [17]

Answer: V = 108\pi = 339.292 inches^3

Step-by-step explanation:

-The equation for the volume of the cone, is:

V=\frac{1}{3} \pi r^2h

-Place your measurements of radius and the height onto the equation:

V=\frac{1}{3} \pi 6^29

-Then you solve them:

V=\frac{1}{3} × \pi × 6^2 × 9

V=\frac{1}{3} × \pi × 36 × 9

V= \frac{36}{3}\pi × 9

V= 12\pi × 9

V=108\pi =339.292

3 0
3 years ago
Calculate:<br>a) QR <br>b) PS <br>c) The area of quadrilateral PQRS
Zigmanuir [339]

<em>Greetings from Brasil...</em>

For QR: we need to use the Sine Law in Any Triangle....

QS/SEN 72 = QR/SEN 25

6/SEN 72 = QR/SEN 25

6,3 = QR/SEN 25

<h3>QR = 2,66</h3>

For PS: we need to use the Cosine Law in Any Triangle....

PS² = PQ² + QS² - 2.PQ.QS.COS Q

PS² = 7,4² + 6² - 2.(7,4).6.COS 34

PS² = 90,76 - 73,61

PS = √17,14

<h3>PS = 4,14</h3>

For area we use Heron's Formula 2x.....

for ΔQRS = A1:

A1 = √[P.(P - QR).(P - RS).(P - QS)]

<em>where P = (QR + RS + QS)/2</em>

<em>A1 = </em>√[P.(P - QR).(P - RS).(P - QS)]

<em>      </em><em>RS = 6,26 </em><em>(using RS/SEN 97 = QS/SEN 72)</em>

P = (2,66 + 6,26 + 6)/2

P = 14,92/2 ⇒ P = 7,46

A1 = √[7,46.(7,46 - 2,66).(7,46 - 6,26).(7,46 - 6)]

A1 = 7,92

for ΔPQS = A2:

A2 = √[P.(P - PQ).(P - PS).(P - QS)]

P = (7,4 + 4,14 + 6)/2 = 8,77

A2 = √[8,77.(8,77 - 7,4).(8,77 - 4,14).(8,77 - 6)]

A2 = 12,41

Total Area = A1 + A2

Total Area = 7,92 + 12,41

<h3>Total Area = 20,33</h3>

<em>see more:</em>

brainly.com/question/17138076

3 0
3 years ago
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