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2 years ago

Shape B is 2 times the size of Shape A. Which is the perimeter of Shape B? (1 point)

Mathematics

1 answer:

Klio2033 [76]2 years ago

5 0

Answer:

Step-by-step explanation:

multiple 1 and 4 by 2 and you will get 2 and 8. Then multiply 2 and 8 and you get 16

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Is (x+5) A FACTOR OF f(x) = x3 − 4x2 + 3x + 7

AlekseyPX

Answer:

(x+5) is not a factor of f(x)

Step-by-step explanation:

Step 1 : we solve the equation x +5 = 0

x + 5 = 0 then x = -5

Step 2: we plug in -5 into f(x)

If we get zero then x+5 is a factor of f(x)

If we get a number other than zero then x+5 is not a factor of f(x)

Calculation:

f(-5) = (-5)³ − 4(-5)² + 3(-5) + 7 = - 233

Since we got -233 and not 0

Therefore ,(x+5) is not a factor of f(x)

8 0

1 year ago

Read 2 more answers

Suppose you are given information about a triangle according to SSS, SAS, and ASA. For which of these can you immediately use th

jek_recluse [69]

Answer:

SSS and SAS

Step-by-step explanation:

Law of cosines: The law of cosines is used for calculating one side of a triangle when the angle opposite and the other two sides are known.

If the information about a triangle according to SSS, SAS and ASA is given, then we will immediately use SSS and SAS by using the law of cosines to find one of the remaining measures because Law of cosines is applied if we know one angle opposite and the other two sides.

Also, in ASA, we know two angles and one side, thus we cannot use Law of cosines in this, rather Law of sines can be accurately use in this case.

if you have two sides, encroaching an angle, then the Law of Cosines can be used to find a missing side, thus SAS will work fine for that, now, if you have no angles given, but you know all sides, you can use the Law of Cosines as well, by solving it for the angle, and get the angles, on which case, SSS will do... .now as far as ASA, if you have two angles and one side known, then... that's not very workable for the law of cosines

please mark me brainliest :)

3 0

3 years ago

Read 2 more answers

An oil tanker can be emptied by the main pump in 5 hours. An auxiliary pump can empty the tanker in 7 hours. If the main pump is

r-ruslan [8.4K]

Answer:

so the answer will be 1

Step-by-step explanation:

An oil tanker can be emptied by the main pump in 5 hours.

An auxilary pump can empty the tanker in 14 hours.

If the main pump is started at 7pm, when should the auxilary pump be started

so that the tanker is emptied by 11pm?

Let t = no. of hrs to run the Aux pump

The main pump will run 4 hr (7 - 11 pm)

Let the completed job = 1; (an empty Tanker)

The shared work equation

4%2F5 + t%2F14 = 1

Multiply equation by 70 to get rid of the equation, results:

14(4) + 5t = 70

56 + 5t = 70

5t = 70 - 56

5t = 14

t = 14%2F5

t = 2.8 hrs to run the aux pump

2.8 hr = 2 + .8(60) = 2 hrs 48 min

Subtract 2:48 from 11:00 = 8:12 PM start the aux pump

;

Check solution

4/5 + 2.8/14 =

.8 + .2 = 1

6 0

2 years ago

An acre measures 4840 square yards. In a city, a lot on which a single-

belka [17]

The lot is 9.2% of the an acre.

Given:

Area of an acre = 4840 sq. yards

Area of lot = 40 by 100 ft = $40 ]\times 100 = 4,000 $ ft^{2}$

Convert the area of the lot to feet ( $9 ft^{2} = yd^{2}$ ):

Therefore:

Area of lot = $\frac{4,000}{9} = 444.4 $ yd^{2}$

Percentage occupied by the lot = area of lot / area of acre x 100

$= \frac{444.4}{4840} \times 100\\\= 9.2$

The lot therefore is 9.2% of the an acre.

Learn more here:

brainly.com/question/20730855

7 0

2 years ago

Plz Help Only 1 question 24 POINTS

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Cat 31 10 41
No cat 24 7 31
Total 55 17 144

4 0

3 years ago