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EleoNora [17]
3 years ago
6

PLEASE HELPPPP ASAP!!!! I REALLY NEED IT! WILL MARK BRAINLIEST!!!!

Mathematics
1 answer:
11Alexandr11 [23.1K]3 years ago
6 0

Answer:

3.3

Step-by-step explanation:

d = (10 - 4) + (8 - 3)

d = 6 + 5

d = square root of 11

d = 3.31662479 or 3.3

I'll be expecting that brainliest :)

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X^2-7x-6=0<br> Use the quadratic formula to complete the equation show step by step
asambeis [7]

Answer:

x  = 7  ± √73   / 2



3 0
3 years ago
Read 2 more answers
Record for Boston Marathon's wheelchair division is 1 hour, 18 minutes, and 27 seconds.
aleksley [76]
1 hr 18 minutes and 27 seconds hmmm

there are 60 minutes in 1 hr, thus 18 minutes is 18/60 hrs or 0.3hr.

so 1hr 18min is 1.3 hrs

there are 60 seconds in 1 minute and 60 minutes in 1 hr, thus 60*60 seconds in 1hr, or 3600 seconds, so, 27 seconds is just 27/3600 hrs, or 0.0075 hrs.

so, 1.3 hr or 1.3000 hr for that matter plus 0.0075, is just 1.3075 hrs.

a)

so, they covered 26.2 miles in 1.3075 hrs, so the average speed is just 26.2/1.3075, or about 20.0382409177 miles/hr

b)

\bf \begin{array}{ccll}&#10;miles&hrs\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;26.2&1.3075\\&#10;30&h&#10;\end{array}\implies \cfrac{26.2}{30}=\cfrac{1.3075}{h}\implies h=\cfrac{1.3075\cdot 30}{26.2}

8 0
4 years ago
Find the slope please using the formula
Aleks04 [339]

Answer:

4/3

Step-by-step explanation:

Using the formula of rise/run:

9-1 = 8

8-2 = 6

8/6 =4/3

3 0
3 years ago
Calcula el área de un rombo cuya diagonal mayor mide 10 cm y cuya diagonal menor es la mitad de la mayor.
attashe74 [19]

Respuesta:

25 cm²

Explicación paso a paso:

El área A de un rombo tiene:

A = pq / 2

Donde pyq son las diagonales

Tomando p como la diagonal más grande = 10 cm

Diagonal más pequeña, q = 1/2 * 10 = 5cm

Por lo tanto, el área del rombo es:

A = (10 * 5) / 2

A = 50/2

A = 25 cm²

5 0
3 years ago
A large corporation starts at time t = 0 to invest part of its receipts continuously at a rate of P dollars per year in a fund f
Andrews [41]

Answer:

A = \frac{P}{r}\left( e^{rt} -1 \right)

Step-by-step explanation:

This is <em>a separable differential equation</em>. Rearranging terms in the equation gives

                                                \frac{dA}{rA+P} = dt

Integration on both sides gives

                                            \int \frac{dA}{rA+P} = \int  dt

where c is a constant of integration.

The steps for solving the integral on the right hand side are presented below.

                               \int \frac{dA}{rA+P} = \begin{vmatrix} rA+P = m \implies rdA = dm\end{vmatrix} \\\\\phantom{\int \frac{dA}{rA+P} } = \int \frac{1}{m} \frac{1}{r} \, dm \\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \int \frac{1}{m} \, dm\\\\\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |m| + c \\\\&\phantom{\int \frac{dA}{rA+P} } = \frac{1}{r} \ln |rA+P| +c

Therefore,

                                        \frac{1}{r} \ln |rA+P| = t+c

Multiply both sides by r.

                               \ln |rA+P| = rt+c_1, \quad c_1 := rc

By taking exponents, we obtain

      e^{\ln |rA+P|} = e^{rt+c_1} \implies  |rA+P| = e^{rt} \cdot e^{c_1} rA+P = Ce^{rt}, \quad C:= \pm e^{c_1}

Isolate A.

                 rA+P = Ce^{rt} \implies rA = Ce^{rt} - P \implies A = \frac{C}{r}e^{rt} - \frac{P}{r}

Since A = 0  when t=0, we obtain an initial condition A(0) = 0.

We can use it to find the numeric value of the constant c.

Substituting 0 for A and t in the equation gives

                         0 = \frac{C}{r}e^{0} - \frac{P}{r} \implies \frac{P}{r} = \frac{C}{r} \implies C=P

Therefore, the solution of the given differential equation is

                                   A = \frac{P}{r}e^{rt} - \frac{P}{r} = \frac{P}{r}\left( e^{rt} -1 \right)

4 0
3 years ago
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