Let us assume the larger number = x
Let us assume the smaller number = y
Then
x + y = 3 3/4
x + y = 15/4
And
x/3 = (2y/3) + 1/2
x = [3 * (2y/3)] + (3/2)
= 2y + (3/2)
Now putting the value of x from the second equation to the first , we get
x + y = 15/4
2y + (3/2) + y = 15/4
3y = (15/4) - (3/2)
3y = (15 - 6)/4
3y * 4 = 9
12y = 9
y = 9/12
= 3/4
Now putting the value of y in the first equation, we get
x + y = 15/4
x + (3/4) = (15/4)
x = (15/4) - (3/4)
= (15 - 3)/4
= 12/4
= 3
So the value of x or the larger number is 3 and the value of y or the smaller number is 3/4.
99.69/100=.9969
.9969*20=19.938
Ramon would receive ~ $19.94
F(g(3))
f(4 * 3^2 + 9)
f(45)
3 * 45 - 1
134
F(g(2))
g(x) = x^2 - 6x - 7
g(2) = 2^2 - 6(2) - 7
g(2) = 4 - 12 - 7
g(2) = -15
f(x) = x + 8
f(g(2) = f(-15) = -15 + 8 = -7 <==
ur answer is -7
