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3 years ago

The following situation applies to questions 2-5.

Mathematics

1 answer:

vivado [14]3 years ago

6 0

Answer:

7c + 668 > 2000

Step-by-step explanation:

Given that :

Target = more than. 2000 food cans

Amount already collected = 668 food cans

Food can remaining to collect per day within 7 days = 2000 - 668

Let number of cans left to collect per day with 7 days = c

7 * c + cans already collected > target

7c + 668 > 2000

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4. Using the geometric sum formulas, evaluate each of the following sums and express your answer in Cartesian form.

nikitadnepr [17]

Answer:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=1$

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=0$

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})=\frac{1}{2}$

Step-by-step explanation:

$\sum_{n=0}^9cos(\frac{\pi n}{2})=\frac{1}{2}(\sum_{n=0}^9 (e^{\frac{i\pi n}{2}}+ e^{\frac{i\pi n}{2}}))$

$=\frac{1}{2}(\frac{1-e^{\frac{10i\pi}{2}}}{1-e^{\frac{i\pi}{2}}}+\frac{1-e^{-\frac{10i\pi}{2}}}{1-e^{-\frac{i\pi}{2}}})$

$=\frac{1}{2}(\frac{1+1}{1-i}+\frac{1+1}{1+i})=1$

2nd

$\sum_{k=0}^{N-1}e^{\frac{i2\pi kk}{2}}=\frac{1-e^{\frac{i2\pi N}{N}}}{1-e^{\frac{i2\pi}{N}}}$

$=\frac{1-1}{1-e^{\frac{i2\pi}{N}}}=0$

3th

$\sum_{n=0}^\infty (\frac{1}{2})^n cos(\frac{\pi n}{2})==\frac{1}{2}(\sum_{n=0}^\infty ((\frac{e^{\frac{i\pi n}{2}}}{2})^n+ (\frac{e^{-\frac{i\pi n}{2}}}{2})^n))$

$=\frac{1}{2}(\frac{1-0}{1-i}+\frac{1-0}{1+i})=\frac{1}{2}$

What we use?

We use that

$e^{i\pi n}=cos(\pi n)+i sin(\pi n)$

and

$\sum_{n=0}^k r^k=\frac{1-r^{k+1}}{1-r}$

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3 years ago

Find the value for y that makes the statment true y÷4=44

Dmitry [639]

Answer:

y=176

Step-by-step explanation:

176/4= 44

44x4=176

So, the answer is 176

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polet [3.4K]

Answer:

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Step-by-step explanation:

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3 years ago

Which of the following expressions is equivalent to -g/h?

Stolb23 [73]

The correct answer is A

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2 years ago

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The probability that a student takes a history class and a sociology class is 0.051. The probability that a student takes a hist

oee [108]

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3 years ago

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