Given that
log (x+y)/5 =( 1/2) {log x+logy}
We know that
log a+ log b = log ab
⇛log (x+y)/5 =( 1/2) log(xy)
We know that log a^m = m log a
⇛log (x+y)/5 = log (xy)^1/2
⇛log (x+y)/5 = log√(xy)
⇛(x+y)/5 = √(xy)
On squaring both sides then
⇛{ (x+y)/5}^2 = {√(xy)}^2
⇛(x+y)^2/5^2 = xy
⇛(x^2+y^2+2xy)/25 = xy
⇛x^2+y^2+2xy = 25xy
⇛x^2+y^2 = 25xy-2xy
⇛x^2+y^2 = 23xy
⇛( x^2+y^2)/xy = 23
⇛(x^2/xy) +(y^2/xy) = 23
⇛{(x×x)/xy} +{(y×y)/xy} = 23
⇛(x/y)+(y/x) = 23
Therefore, (x/y)+(y/x) = 23
Hence, the value of (x/y)+(y/x) is 23.
Answer is c..they worship different gods
Answer: 37
Step-by-step explanation:
Answer:
100
Step-by-step explanation:
Isosceles triangle have 2 equal angles. Therefore the second angle in the triangle will also be 25.
Since the sum of angles in a triangle is 180.
180-(25x2) will give you the last angle in one of the triangles.
The other angle is identical so the angle at the top of the other triangle will also be 130.
The sum of angles in a circle is 360.
Therefore, angle x = 360-(130x2)
X= 100
